(a) The amplitude of the wave is 3 cm.
(b) The speed of the wave is 19.6 m/s
(c) The angular frequency is 653.72 rad/s.
(d) The period of the wave is 0.0096 s.
(e) The wavelength of the wave is 0.392 m.
<h3>
Speed of the wave</h3>
The speed of the wave is calculated as follows;
where;
- μ is mass per unit length = (0.26 kg)/(2 m) = 0.13 kg/m
- T is tension
<h3>Angular frequency</h3>
ω = v/r
ω = v/A
ω = 19.6/0.03
ω = 653.72 rad/s
<h3>Period of the wave</h3>
<h3>Wavelength</h3>
v = fλ
λ = v/f
λ = 19.6/50
λ = 0.392 m
Learn more about wavelength here: brainly.com/question/10728818
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We use the first equation of motion, to calculate the acceleration of the car
Here, v is final velocity and its value is 100 km/h = 100(1000/3600) = 27 .78 m/s and u is initial velocity as car accelerates from rest so its value zero and t is time taken and its value is given 4.80 s.
Therefore,
.
Now the magnitude of force,
.
Thus, the magnitude of force by passenger experience during the acceleration is 393 .52 \ N.
Answer:
(c) 0.77 m/s^2 directed 35° south of west.
Explanation:
Let's first find the resultant force and its direction:
F = 20.808 N
To find the direction, we can just imagine the forces as lengths of a right angled triangle.
So, Force (west) will be our perpendicular.
and Force (south) will be our base.
Calculating the angle we have:
Theta = 54.78° (angle from south)
Direction of resultant force = 90 - 54.78 = 35.22° (south of west)
Taking out the acceleration, we get:
F = m * a
20.808 = 27 * a
a = 0.77 m/s^2
So the answer is (c)
It has 178200000 ms^-1 and the train has 25200000ms^-1.