Question

A 450-kg sports car accelerates from rest to 100 km/h in 4.80 s. what magnitude force does a 68.0 kg passenger experience during the acceleration?

Answer 1

We use the first equation of motion, to calculate the acceleration of the car

$v = u + at$

Here, v is final velocity and its value is 100 km/h = 100(1000/3600)  =  27 .78 m/s  and u is initial velocity as car accelerates from rest so its value zero and t is time taken and its value is given 4.80 s.

Therefore,

$27 .78 \ m/s = 0 + a \times 4.80 \ s \\\\ a = 5.79 \ m/s^2$.

Now the magnitude of force,

$F= ma = 68 \ kg \times 5.79 \ m/s^2 = 393 .52 \ N$.

Thus, the magnitude of force by passenger experience during the acceleration is 393 .52 \ N.