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laila [671]
3 years ago
10

A 450-kg sports car accelerates from rest to 100 km/h in 4.80 s. what magnitude force does a 68.0 kg passenger experience during

the acceleration?
Physics
1 answer:
Vinil7 [7]3 years ago
5 0

We use the first equation of motion, to calculate the acceleration of the car

v = u + at

Here, v is final velocity and its value is 100 km/h = 100(1000/3600)  =  27 .78 m/s  and u is initial velocity as car accelerates from rest so its value zero and t is time taken and its value is given 4.80 s.

Therefore,

27 .78 \ m/s = 0 + a \times 4.80 \ s \\\\ a = 5.79 \ m/s^2.

Now the magnitude of force,

F= ma = 68 \ kg \times 5.79 \ m/s^2 =  393 .52 \ N.

Thus, the magnitude of force by passenger experience during the acceleration is 393 .52 \ N.

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Hope this helps.


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4 0
2 years ago
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A ball is thrown straight up. What are the velocity and acceleration of the ball at the highest point in its path?
zubka84 [21]

Answer:

b. v = 0, a = 9.8 m/s² down.

Explanation:

Hi there!

The acceleration of gravity is always directed to the ground (down) and, near the surface of the earth, has a constant value of 9.8 m/s². Since the answer "b" is the only option with an acceleration of 9.8 m/s² directed downwards, that would solve the exercise. But why is the velocity zero at the highest point?

Let´s take a look at the height function:

h(t) = h0 + v0 · t + 1/2 g · t²

Where

h0 = initial height

v0 = initial velocity

t = time

g = acceleration due to gravity

Notice that the function is a negative parabola if we consider downward as negative (in that case "g" would be negative). Then, the function has a maximum (the highest point) at the vertex of the parabola. At the maximum point, the slope of the tangent line to the function is zero, because the tangent line is horizontal at a maximum point. The slope of the tangent line to the function is the rate of change of height with respect to time, i.e, the velocity. Then, the velocity is zero at the maximum height.

Another way to see it (without calculus):

When the ball is going up, the velocity vector points up and the velocity is positive. After reaching the maximum height, the velocity vector points down and is negative (the ball starts to fall). At the maximum height, the velocity vector changed its direction from positive to negative, then at that point, the velocity vector has to be zero.

8 0
3 years ago
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Mrrafil [7]

Answer:

Option A

Explanation:

At segment T-U, the substance changes from a liquid to a gas and does not change temperature.

The reason is because latent heat of vaporisation allows for the absorption of heat in the change of state and temperature remains constant until it has fully changed state.

4 0
1 year ago
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Alchen [17]
If the object is in equilibrium that means that the sum of the forces on it is zero and the net force is zero. If none of the forces changes then the object continues in constant uniform motion. That means constant speed in a straight line.
8 0
3 years ago
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HELP ASAP! GIVING BRAINLIEST!!!<br><br> I need the answers to 1,2,3!!
artcher [175]

1) 72/4 = 18 years

2) 72/10 = 7.2 years

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