The hiker followed the north trail a distance of two kilometers in thirty minutes is an example that provides a complete scientific description of an object in motion.
<span>.87 m/s^2 ,hope this helps!!!!!!</span>
Initial speed, u = 15 m/s
Final speed, v = 10 m/s
Distance traveled, s = 6.0 m
The acceleration, a, is determined from
u² + 2as = v²
(15 m/s)² + 2*(a m/s²)*(6.0 m) = (10 m/s)²
225 + 12a = 100
12a = -125
a = -10.4167 m/s²
The time, t, for the velocity to change from 15 m/s to 10 m/s is given by
(10 m/s) = (15 m/s) - (10.4167 m/s²)*(t s)
10 = 15 - 10.4167t
t = 0.48 s
The average speed is
(6.0 m)/(0.48 s) = 12.5 m/s
Answer: 12.5 m/s
Answer:
5437.5 N
Explanation:
from the question we are given the following:
mass = 7.25 kg
initial speed (u) = 10.5
finial velocity (v) = 0
compression (s) = -7.35 cm = -0.0735 m (the negative sign is because the face is compressed, so there is a decrease)
we know that force = mass x acceleration,
we have our mass but need to find the acceleration. we can get the acceleration by applying the formula below
therefore
0 = 10.5^{2} + (-2)× a × 0.0735[/tex]
a = }[/tex]
a = 750
from F = m x a
force = 7.25 x 750 = 5437.5 N
Answer:
The magnetic flux density is 3 x 10⁵ Wb/m²
Explanation:
Given;
magnetic flux of each line of force, Ф = 30 Wb
area of the bar magnet, A = 1 cm² = 1 x 10⁻⁴ m²
The flux density of the magnet is the measure of the concentration of the magnetic flux per unit area. The unit is Wb/m² or Tesla.
B = Ф / A
B = 30 / (1 x 10⁻⁴ )
B = 3 x 10⁵ Wb/m²
Therefore, the magnetic flux density is 3 x 10⁵ Wb/m²