In Cathode Ray Oscilloscope (CRO), if plates for vertical deflection are removed then what will be the wave pattern on the fluor
1 answer:
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Answer:
The maximum speed of the wing tip is 1.25 m/s
Explanation:
In simple harmonic motion, the body experiences a restoring force whose magnitude is directly proportional to the distance from its mean position and its direction is towards the mean position.
The speed in the case of simple harmonic motion is given by the equation :
v = Aωsinωt
Here A is maximum displacement, t is time and ω is the angular frequency of oscillation.
For maximum speed, sinωt = 1 . So, the above equation becomes:
v = Aω
But, ω = 2πf , here f is the frequency of oscillation. So,
v = A x 2πf .....(1)
In this problem,
Frequency of oscillation, f = 40 Hz
Total distance between the upper and lower limits of motion of wing tip is equal to the twice of maximum displacement of the wing tip from the equilibrium position, i.e. ,
2 x A = 1 cm
A = 0.5 cm = 0.5 x 10⁻² m
Substitute the value of f and A in equation (1).
v = 1.25 m/s
Answer:
0.196*c
Explanation:
A good thing to remember is that once you have the position and the time in one frame we can figure out corresponding position and time in another frame in other frames given their relative velocities.
Anna moves in (S') frame and we are given two events synchronized in her frame with the distance between them, Hence using Lorentz transformation to show which event Bob frame (S) will see first:
Hence,
we are assuming that dx' > 0 , hence we are saying that light emitted from front end of the plane is event number two and that coming from the back end is event number one. As the time in Bob's frame turns out to be positive, this means that event number two happened after event number one in his frame, in other words, the light emitted from the back end of Anna's plane arrives first to Bob's eyes.
Given:
dt' = 40ns
dt = 0
dx' = 60
Solution: