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3 years ago

15

In Cathode Ray Oscilloscope (CRO), if plates for vertical deflection are removed then what will be the wave pattern on the fluor

escent screen?

1 answer:

krek1111 [17]3 years ago

3 0

Answer:

the waves will appear horizontally on the florescent screen because the y-plates have been removed

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How much water can be held by a cylindrical tank with a radius of 12 feet and a height of 30 feet? A. 2,260.8 cubic feet B. 13,5

MakcuM [25]

Answer:

Volume, V = 13564.8 cubic feet

Explanation:

It is given that,

Radius of the cylindrical tank, r = 12 feet

Height of the tank, h = 30 feet

We need to find the water that can be held by a cylindrical tank i.e. we need to find the volume of the tank. It is given by :

$V=\pi\times r^2\times h$

$V=3.14\times (12)^2\times 30$

V = 13564.8 cubic feet

So, the water held by the tank is 13564.8 cubic feet. Hence, this is the required solution.

6 0

3 years ago

Find the distance along an arc on the surface of the earth that subtends a central angle of 1 minutes (1 minute = 1/60 degree).

-Dominant- [34]

Answer:

1.152 miles

Explanation:

Given: central angle = 1 minute = $(\frac{1}{60}) ^{o}$

radius of the earth = 3960 miles

The length of an arc = $\frac{\alpha }{360^{o} }$ 2 $\pi$ r

where: $\alpha$ is the central angle, and r is the radius.

Thus,

Distance along the arc = $\frac{\alpha }{360^{o} }$ 2 $\pi$ r

Distance along the arc = $\frac{(\frac{1}{60}) ^{o} }{360^{o} }$ x 2 x $\frac{22}{7}$ x 3960

= $\frac{(\frac{1}{60}) ^{o} }{360^{o} }$ x 24891.4286

= 1.1524

The required distance along an arc is 1.152 miles.

4 0

4 years ago

Please help. Possibly more than one answer:

attashe74 [19]

Answer:

air friction

Explanation:

this helps with take of and landing.

4 0

3 years ago

a car traveling north with a velocity of 29m/s changes its velocity to 36 in the span of 11s. What was the car's acceleration du

Nikolay [14]

Answer:

I’m so sorry I tried solving it but I don’t understand it can you explain the question a little bit more ty

Explanation:

8 0

4 years ago

A 20 kg mass is moving at 10 m/s and collides with a stationary 5 kg mass, transferring all its momentum in the collision, what

Fudgin [204]

Answer:

v = 40 [m/s].

Explanation:

Linear momentum is defined as the product of mass by Velocity. In this way, by means of the following equation, we can calculate the momentum.

$P=m*v\\$

where:

m = mass [kg]

v = velocity [m/s]

$P =20*10\\P =200 [kg*m/s]$

Since all momentum is transferred, we can say that this momentum is equal for the mass of 5 [kg]. In this way, we can determine the speed after the impact.

$v = P/m\\v = 200/5\\v = 40 [m/s]$

3 0

3 years ago