Answer:
7.08
Explanation:
To solve this problem we'll use the <em>Henderson-Hasselbach equation</em>:
- pH = pka + log
![\frac{[A^-]}{[HA]}](https://tex.z-dn.net/?f=%5Cfrac%7B%5BA%5E-%5D%7D%7B%5BHA%5D%7D)
Where is the ratio of [sodium formate]/[formic acid] and pka is equal to -log(Ka), meaning that:
- pka = -log (1.8x10⁻⁴) = 3.74
We<u> input the data</u>:
- 4.59 = 3.74 + log
And<u> solve for </u>:
- 0.85 = log
=
- = 7.08
60mol O2 × 1 mol C6H12O6 / 6 moles 02 = 10 moles of Glucose
The last equation you have written out would be the correct single replacement reaction.
The mass of KCl per volume of solution=.35X(35.5+39)=26.075g/L
Answer:
there is no change in mass
Explanation
<em>ye</em>
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