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kotykmax [81]
3 years ago
12

5.) A spring with a spring constant of 500 n/m is stretched 1 meter in

Chemistry
1 answer:
Ymorist [56]3 years ago
4 0

Answer:

250J

Explanation:

Given parameters:

Spring constant  = 500N/m

Extension  = 1m

Unknown:

Elastic potential energy  = ?

Solution:

The elastic potential energy of a body is the energy stored within an elastic string.

  EPE  = \frac{1}{2} k e²

k is the spring constant

e is the extension

 Now;

      EPE  =  \frac{1}{2}  x 500 x 1²   = 250J

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