Question

5.) A spring with a spring constant of 500 n/m is stretched 1 meter in

Answer 1

Answer:

250J

Explanation:

Given parameters:

Spring constant  = 500N/m

Extension  = 1m

Unknown:

Elastic potential energy  = ?

Solution:

The elastic potential energy of a body is the energy stored within an elastic string.

  EPE  = $\frac{1}{2}$ k e²

k is the spring constant

e is the extension

 Now;

      EPE  =  $\frac{1}{2}$  x 500 x 1²   = 250J