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3 years ago

Can someone help me please

Physics

1 answer:

makvit [3.9K]3 years ago

3 0

Answer:

Time, I believe. Pretty sure it's time lol

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A uniform drawbridge must be held at a 37 ? angle above the horizontal to allow ships to pass underneath. The drawbridge weighs

iVinArrow [24]

Answer:

Explanation:

a ) Let T be tension in the horizontal cable .

Taking torque about hinge of weight and tension

45000 x 7 x cos37 = 3.5 sin 37 x T

T = 119431 N

b ) If R be the reaction force on the hinge

R sin 37 = 45000 ( vertical force balancing each other )

R = 74775 N

c ) The direction of R will be along the bridge

d ) Moment of inertia of bridge

I = Ml² / 3 = (45000 / 9.8 ) x 14² / 3

= 300000.

When cable breaks , the weight creates a torque about the hinge will creates angular acceleration

Torque by weight about the hinge

= 45000 x 7 x cos 37

= 251570

angular acceleration = torque / moment of inertia

= 251570 / 300000

= .84 radian / s²

4 0

3 years ago

How much would your 20.0 kg dog weigh on Neptune?

Agata [3.3K]

F= 6m.m2/r^2

F= (6.673x10^-11)(70)(3.32x10^23)/(2.44x10^6)^2

ANS: F= 260 N=2.60x10^2 N

7 0

3 years ago

Read 2 more answers

If the masses of objects increase and their distance from each other remains the same, then the force of gravity between the two

skelet666 [1.2K]

Answer:

the formula for the force of gravity depends inversely of the distance and directly of the masses.

$F_{G} =G\frac{M_{1} M_{2}}{R^{2}}$

This means that if the masses increase and their distance remains the same the force will increase proportionally.

4 0

3 years ago

What is the measure of how much a material resists the formation of an electric field?

shusha [124]

The answer is c capacitance

5 0

4 years ago

A plastic film moves over two drums. During a 4-s interval the speed of the tape is increased uniformly from v0 = 2ft/s to v1 =

Ratling [72]

Answer:

Question 1)

a) The speed of the drums is increased from 2 ft/s to 4 ft/s in 4 s. From the below kinematic equations the acceleration of the drums can be determined.

$v_1 = v_0 + at \\4 = 2 + 4a\\a = 0.5~ft/s^2$

This is the linear acceleration of the drums. Since the tape does not slip on the drums, by the rule of rolling without slipping,

$v = \omega R\\a = \alpha R$

where α is the angular acceleration.

In order to continue this question, the radius of the drums should be given.

Let us denote the radius of the drums as R, the angular acceleration of drum B is

α = 0.5/R.

b) The distance travelled by the drums can be found by the following kinematics formula:

$v_1^2 = v_0^2 + 2ax\\4^2 = 2^2 + 2(0.5)x\\x = 12 ft$

One revolution is equal to the circumference of the drum. So, total number of revolutions is

$x / (2\pi R) = 6/(\pi R)$

Question 2)

a) In a rocket propulsion question, the acceleration of the rocket can be found by the following formula:

$a = \frac{dv}{dt} = -\frac{v_{fuel}}{m}\frac{dm}{dt} = -\frac{13000}{2600}25 = 125~ft/s^2$

b) $a = -\frac{v_{fuel}}{m}\frac{dm}{dt} = - \frac{13000}{400}25 = 812.5~ft/s^2$

5 0

4 years ago