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777dan777 [17]
3 years ago
13

Describe the role of C-S-H in providing strength for cement. Discuss which compounds produce C-S-H and why balancing the amounts

of those compounds is important.
Engineering
1 answer:
wariber [46]3 years ago
8 0

Answer:

Following are the solution to this question:

Explanation:

Whenever a chemical reaction occurs between water and cement the heat is released, and a CaOSiO_2H_2O (C-S-H gel) gel constructs gel is also recognized as "tobermorite gel."

This one gel acts like a pack of gum and also has a cement quality, that holds its particles intact and therefore contributes to the overall compression mix. An increase in supply explicitly causes the movement in the outcome of power. C3S and C2S are both the compounds of Bouge that produce hydration C-S-H gel.

It mixture must be balanced as Ca(OH)_2 with C-S-H gel also is given as a byproduct. It Ca(OH)_2 , that cause sudden with sulphate and form CaSO_4 , is an unacceptable substance. Sulfate attack or later deterioration of its cement is caused by this CaSO_4 .

All C3S and C2S generate various amounts of C-S-H gel so, the required strength can be maintained without compromising on real term durability.

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Who would most likIf you are interested in working for a specific company, what type of job site should you look at for opening?
fredd [130]

Answer:

if you are interested in working for a company then you should opt for c). Company Site

Explanation:

Industries can have the same scope of work but every company has their own way of achieving objectives. You should learn about the company, its job functions and the specific sector you're interested in. Review the current projects they are working on (specific to your job function), and how you can benefit the company on those projects.

5 0
3 years ago
Read 2 more answers
4. Which of the following are used for vehicle and/or major component identification?
AleksAgata [21]

Option C

VIN (vehicle identification number) are used for vehicle and/or major component identification

<h3><u>Explanation:</u></h3>

American automobile producers have practiced a vehicle identification number (V.I.N.) to name and recognize motor vehicles. They serve to retain an indication of obstacles, ownership exchanges, and prevent crime. This practice also posted the superimposed major component parts and replacement parts to be noted for each of the classes of vehicles.

Depending on the transport major parts may be marked with the vehicle’s VIN. The component part labels are composed of the alike material as the Federal Safety Certification Labels and are also planned to self destruct if excluded.

4 0
4 years ago
Which kind of fracture (ductile or brittle) is associated with each of the two crack propagation mechanisms?
Nina [5.8K]

dutile is the correct answer

6 0
3 years ago
2. Recycled tires are frequently turned into?
Leya [2.2K]

Answer:vmmjhnv

Explanation:

b m bn

6 0
3 years ago
A piston–cylinder device contains a mixture of 0.5 kg of H2 and 1.2 kg of N2 at 100 kPa and 300 K. Heat is now transferred to th
Taya2010 [7]

Answer:

(a) The heat transferred is 2552.64 kJ    

(b) The entropy change of the mixture is 1066.0279 J/K

Explanation:

Here we have

Molar mass of H₂ = 2.01588 g/mol

Molar mass of N₂ = 28.0134 g/mol

Number of moles of H₂ = 500/2.01588  = 248 moles

Number of moles of N₂ = 1200/28.0134 = 42.8 moles

P·V = n·R·T

V₁ = n·R·T/P = 290.8×8.3145×300/100000 = 7.25 m³

Since the volume is doubled then

V₂ = 2 × 7.25 = 14.51 m³

At constant pressure, the temperature is doubled, therefore

T₂ = 600 K

If we assume constant specific heat at the average temperature, we have

Heat supplied = m₁×cp₁×dT₁ + m₂×cp₂×dT₂

 cp₁ = Specific heat of hydrogen at constant pressure = 14.50 kJ/(kg K

cp₂ = Specific heat of nitrogen at constant pressure = 1.049 kJ/(kg K

Heat supplied = 0.5×14.50×300 K+ 1.2×1.049×300 =  2552.64 kJ    

b)  \Delta S = - R(n_A \times lnx_A + n_B \times ln x_B)

Where:

x_A and x_B are the mole fractions of Hydrogen and nitrogen respectively.

Therefore, x_A = 248 /(248 + 42.8) = 0.83

x_B = 42.8/(248 + 42.8) = 0.1472

∴ \Delta S = - 8.3145(248 \times ln0.83 + 42.8 \times ln 0.1472) =  1066.0279 J/K

5 0
3 years ago
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