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faltersainse [42]
3 years ago
12

2. One of the many methods used for drying air is to cool the air below the dew point so that condensation or freezing of the mo

isture takes place. To what temperature must atmospheric air be cooled in order to have humidity ratio of 0.005 lb/lb?
Engineering
1 answer:
REY [17]3 years ago
6 0

Answer:

0.5°c

Explanation:

Humidity ratio by mass can be expressed as

the ratio between the actual mass of water vapor present in moist air - to the mass of the dry air

Humidity ratio is normally expressed in kilograms (or pounds) of water vapor per kilogram (or pound) of dry air.

Humidity ratio expressed by mass:

x = mw / ma                                  (1)

where

x = humidity ratio (kgwater/kgdry_air, lbwater/lbdry_air)

mw = mass of water vapor (kg, lb)

ma = mass of dry air (kg, lb)

It can be as:

x = 0.005 (100) / [(100 - 100)]

x = 0.005 x 100 / (100 - 100)

x = 0.005 x 100 / 0

x = 0.5°c

So the temperature to which atmospheric air must be cooled in order to have humidity ratio of 0.005 lb/lb is 0.5°c

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noname [10]

The program is an illustration of functions in C++

C++ functions are collection of named program statements that are executed when called

<h3>The C++ program</h3>

The program in C++, where comments are used to explain each action is as follows:

#include <iostream>

#include <cmath>

using namespace std;

//This defines the boolean method

bool isoscelesTriangleHeightAndArea(double base, double hypotenuse, double height, double area) {

   //This checks for invalid base and height

   if(base < 0 || hypotenuse < 0){

       return false;

   }

   //This returns true if base and height are valid

   return true;

}

//The main begins here

int main(){

   //This initializes the variables

   double base, hypotenuse, height, area;

   //This gets input for base and hypotenuse

   cout<<"Base: ";    cin>>base;

   cout<<"Hypotenuse: "; cin>>hypotenuse;

   //The calls the boolean method

   bool success = isoscelesTriangleHeightAndArea(base, hypotenuse, height, area);

   //If success is True

   while (success){

       //This calculates height

       height = sqrt(hypotenuse*hypotenuse - (base/2) * (base/2));

       //This calculates area

       area = 0.5 * base * height;

       //This prints height

       cout << "Triangle height is " << height << endl;

       //This prints area

       cout << "Triangle area is " << area << endl;

       //This gets input for base and hypotenuse

       cout<<"Base: ";    cin>>base;

       cout<<"Hypotenuse: "; cin>>hypotenuse;

       bool success = isoscelesTriangleHeightAndArea(base, hypotenuse, height, area);

   }

   cout << "Invalid Input!" << endl;

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Read more about C++ programs at:

brainly.com/question/24833629

#SPJ1

4 0
2 years ago
Anything you want to do in Hootsuite can be found in the ________, with the main workspace in the _________?
Thepotemich [5.8K]

Answer:

Anything you want to do in Hootsuite can be found in the ___ Sidebar_____, with the main workspace in the ___center______

Sidebar; center

Explanation:

The main workspace of the Hootsuite is located in the center.  The sidebar is where the core access to the Hootsuite functionality, like Streams, Inbox, Planner, Analytics, Publisher, and the App Directory, is obtained.  Hootsuite is a media management platform for curating content, scheduling posts, managing team members, and measuring performances.

5 0
3 years ago
Calculate the radius of gyration for a bar of rectangular cross section with thickness t and width w for bending in the directio
SVEN [57.7K]

Answer:

a)R= sqrt( wt³/12wt)

b)R=sqrt(tw³/12wt)

c)R= sqrt ( wt³/12xcos45xwt)

Explanation:

Thickness = t

Width = w

Length od diagonal =sqrt (t² +w²)

Area of raectangle = A= tW

Radius of gyration= r= sqrt( I/A)

a)

Moment of inertia in the direction of thickness I = w t³/12

R= sqrt( wt³/12wt)

b)

Moment of inertia in the direction of width I = t w³/12

R=sqrt(tw³/12wt)

c)

Moment of inertia in the direction of diagonal I= (w t³/12)cos 45=( wt³/12)x 1/sqrt (2)

R= sqrt ( wt³/12xcos45xwt)

4 0
4 years ago
The following true stresses produce the corresponding true plastic strains for a brass alloy: True Stress (psi) True Strain 4840
Assoli18 [71]

Answer:

70,900

Explanation:

Given :

True stress (psi) _____ True strain (psi)

48400 ______________ 0.11

60400 ______________ 0.19

Using ratio simplification :

Let :

s = True stress ; t = true strain

s1 = 48400

s2 = 60400

t1 = 0.11

t2 = 0.19

True stress, s0 ; needed to produce a True plastic strain, tp = 0.26

(s0 - s1) / (s2 - s1) = (tp - t1) / (t2 - t1)

(s0 - 48400)/(60400 - 48400) = (0.26 - 0.11)/(0.19 - 0.11)

(s0 - 48400)/12000 = 0.15/0.08

Cross multiply :

0.08(s0 - 48400) = 0.15 * 12000

0.08s0 - 3872 = 1800

0.08s0 = 1800 + 3872

0.08s0 = 5672

s0 = 5762 / 0.08

s0 = 70,900

The true stress required to produce a true plastic strain of 0.26 is 70,900

5 0
3 years ago
A small vehicle is powered by a pulsejet. The available net thrust is 6000 N and the traveling speed is 200 km/hr. The gases lea
kumpel [21]

Answer:

a) The mass flow rate is 19.71 kg/s

b) The inlet area is 0.41 m²

c) The thrust power is 333.31 kW

d) The propulsive efficiency is 26.7%

Explanation:

Please look at the solution in the attached Word file.

Download docx
4 0
3 years ago
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