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3 years ago

Write a description of your dream car by using powerful adjectives. Write about 100-120 words

Chemistry

1 answer:

hodyreva [135]3 years ago

6 0

Answer:

It was a cold December night shortly after dusk, a likely setting for an event that would prove to be life altering. As fate would have it, this would be the night that I lost the material possession that truly meant the most to me. I would lose the one thing that gave me much pride and joy and excitement. I often think back and liken us to a newlywed couple, for we had only been together for 18 months and were still very much honeymooning. It was a night, a moment, that even now scoffs and mocks me as I travel thither and yonder with her replacement. But she can never be truly replaced and to call my current fix a replacement seems like a sort of blasphemy.

I called her my Blue Angel. That's right! She was a brand new 1999 Atlantic blue Ford Mustang fully equipped with white racing stripes on each side, dark window tint, a rear spoiler, and a post-factory sound system that I installed personally just to complete the "dream ride" effect. We met on April 24, 1999,when my parents introduced us and told me she was all mine as a reward for graduating high school as valedictorian. And what a reward she turned out to be. We went everywhere together. I took her out to eat. When I'd go play ball somewhere, she went with me. Every day from April 24, 1999, to December 22, 2000, we were together. We were bonding in a way a young man can bond with no other, and there truly was no other for me. Other guys had bigger trucks and faster cars, but where my Blue Angel was lacking in size and power, she more than made up for in pure, unadulterated, raw emotion, She never let me down; she was always looking her best and never longing for attention from me or any of the other countless admirers and fans she won over for...

Explanation:

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Oxidation state of Nitrogen in N2O5

balandron [24]

Explanation:

Oxidation state of Nitrogen in N2O5 is +5

7 0

2 years ago

If i have 8 L of 0.25 M solution, how many miles of MgCl2 are present

qaws [65]

Answer:

2 moles

Explanation:

The following were obtained from the question:

Molarity = 0.25 M

Volume = 8L

Mole =?

Molarity is simply defined as the mole of solute per unit litre of solution. It is represented mathematically as:

Molarity = mole of solute/Volume of solution.

With the above equation, we can easily find the number of mole of MgCl2 present in 8 L of 0.25 M MgCl2 solution as follow:

Molarity = mole of solute/Volume of solution.

0.25 = mole of MgCl2 /8

Cross multiply to express in linear form

Mole of MgCl2 = 0.25 x 8

Mole of MgCl2 = 2 moles

Therefore, 2 moles of MgCl2 are present in 8 L of 0.25 M MgCl2 solution

4 0

3 years ago

Why is gunshot residue important for a forensic scientist? What are the potential complications with this type of evidence?

erik [133]

A residue from a gunshot is most likely gun powder, which tells you what kind of bullet was shot and the type of gun that was used to shoot the target/victim/person. Some complications may be that there is more than one gun or weapon which uses that residue, so it may be hard to pinpoint it and the bullet can't really tell you who it is unless there's DNA on the bullet, and the chemicals of the bullet may even destroy evidence.

3 0

3 years ago

Read 2 more answers

Which example best demonstrates Charles’s law?

Liono4ka [1.6K]

Answer:

Explanation:

The Charles law states that the volume of an ideal gas increases when temperature is increased under constant pressure. The pressure inside the balloon is always equal to the atmospheric pressure. Therefore answer A demonstrate the Charles law.

6 0

3 years ago

Read 2 more answers

How many moles of Al are necessary to form 23.6 g of AlBr₃ from this reaction: 2 Al(s) + 3 Br₂(l) → 2 AlBr₃(s) ?

Gnoma [55]

Answer:

0.088 mole of Al.

Explanation:

First, we shall determine the number of mole in 23.6 g of AlBr₃.

This is illustrated below:

Mass of AlBr₃ = 23.6 g

Molar Mass of AlBr₃ = 27 + 3(80) = 267 g/mol

Mole of AlBr₃ =.?

Mole = mass/Molar mass

Mole of AlBr₃ = 23.6 / 267

Mole of AlBr₃ = 0.088 mol

Next, we shall writing the balanced equation for the reaction.

This is given below:

2Al(s) + 3Br₂(l) → 2AlBr₃(s)

From the balanced equation above,

2 moles of Al reacted with 3 mole of Br₂ to 2 moles AlBr₃.

Finally, we shall determine the number of mole of Al needed for the reaction as follow:

From the balanced equation above,

2 moles of Al reacted to 2 moles AlBr₃.

Therefore, 0.088 mole of Al will also react to produce 0.088 mole of AlBr₃.

4 0

3 years ago

Write a description of your dream car by using powerful adjectives. Write about 100-120 words​

Write a description of your dream car by using powerful adjectives. Write about 100-120 words