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anzhelika [568]
3 years ago
14

Paisley has $53 in her piggy bank. Recently she has been saving and that amount has

Mathematics
1 answer:
elixir [45]3 years ago
3 0
The answer would be 129.85

53 x 1.45 = 76.85
76.85 + 53 = 129.85 dollars
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Use the discriminant to determine the number of solutions and types of solutions for the quadratic equation, below. Then answer
Setler79 [48]

Answer:

A. Discriminant = 116

B. Number of solutions for the quadratic equation = 2

C. Type of solutions (circle one):Imaginary

D. Type of solutions (circle one):irrational

Step-by-step explanation:

The given quadratic equation is

{x}^{2}  + 8x = 13

We rewrite in standard form to get;

{x}^{2}  + 8x   - 13 = 0

The discriminant is

D =  {b}^{2}  - 4ac

where a=1, b=8, c=-13

We substitute to get:

D =  {8}^{2}  - 4 \times 1 \times  - 13

D = 64  + 52

D = 116

Since the discriminant is great than zero, we have two distinct real roots

6 0
3 years ago
Find the GCF of 14 and 15. GCF=
AnnZ [28]

Answer:

1

Step-by-step explanation:

14 - 2 x 7

15 - 3 x 5

GCF of 14 and 15: 1

3 0
2 years ago
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Subtract the sum of(8m-7n+6p)and(-3m-4-p)from the sum of (2m+4-3p)and(-m-n-p)
irinina [24]
8m,3n,9p would im guessing make the numbers to the rest of the problem
8 0
3 years ago
1. At a temperature of 22oC, a liquid that has a volume of 5 mL. The liquid also has a mass of 3 grams. What is the density of t
bagirrra123 [75]

Answer:

The first option.

Step-by-step explanation:

Use the density formula: p = m/v

M = mass(3); B = volume(5)

3/5 = .6

Hope this helps! Have a nice day!

5 0
3 years ago
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You deposit $1,000 for years at an interest rate of 2.0%.If the interest is compounded guardedly.How much money would you have a
Stells [14]
Principle(P)=$1000
Rate (r)=2%=0.02
Time=t=4 years
n=no of times the interest is compounded per year=4
Amount (A)=?
Then,
A=P{(1+r/n)}^(n×t)
=1000{1+0.02/4}^(4×4)
=1000×(1.005^16)
=1000 × 1.08307115
=1083.07115
=1083.07 (approx)

Thus at the end of 4 years the amount of money will be Rs 1083.070 approximately.

Hope this helps....
8 0
3 years ago
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