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3 years ago

How much does a person weigh if it takes 700 kg*m/s to move them 10 m/s NEED ASAP

Physics

1 answer:

madreJ [45]3 years ago

5 0

Answer:

$\huge\boxed{m = 70 \ kg}$

Explanation:

Given Data:

Momentum = P = 700 kg m/s

Velocity = v = 10 m/s

Required:

Mass = m = ?

Formula:

P = mv

Solution:

m = P / v

m = 700 / 10

m = 70 kg

$\rule[225]{225}{2}$

Hope this helped!

<h3>~AnonymousHelper1807</h3>

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In the given situation we have equal masses of two solutions A & B, out of which A has lower specific heat which means that a unit mass of solution A requires lesser energy to raise its temperature by 1°C than the solution B.

Since, the masses of both the solutions are same and equal heat is supplied to both, the proportional condition will follow.

We have a formula for such condition,

$Q=m.c.\Delta T$ .....................................(1)

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equal heat is supplied to both the solutions, i.e. $Q_A=Q_B$

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Now, putting the above values

$Q_A=Q_B$

$m_A.c_A. \Delta T_A=m_B.c_B . \Delta T_B\\\\2.0\times \Delta T_A=3.8 \times \Delta T_B\\\\ \Delta T_A=\frac{3.8}{2.0}\times \Delta T_B\\\\\\\frac{\Delta T_{A}}{\Delta T_{B}} = \frac{3.8}{2.0}>1$

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