3 years ago

Help me out please. please

Chemistry

2 answers:

Musya8 [376]3 years ago

8 0

#1 A #b all of the above

Nana76 [90]3 years ago

6 0

I think that question 2 is all of the above. I’m not sure about Question 1. I think that it is also all of the above but I could be wrong.

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3 years ago

What is the pH of a 0.300 M NH₃ solution that has Kb = 1.8 × 10⁻⁵ ? The equation for the dissociation of NH₃ is: NH₃ (aq) + H₂O

nalin [4]

Answer:

11.4

Explanation:

Step 1: Given data

Concentration of the base (Cb): 0.300 M

Basic dissociation constant (Kb): 1.8 × 10⁻⁵

Step 2: Write the dissociation equation

NH₃(aq) + H₂O(l) ⇄ NH₄⁺(aq) + OH⁻(aq)

Step 3: Calculate the concentration of OH⁻

We will use the following expression.

$[OH^{-} ]=\sqrt{Kb \times Cb } = \sqrt{1.8 \times 10^{-5} \times 0.300 } = 2.3 \times 10^{-3} M$

Step 4: Calculate the pOH

We will use the following expression.

$pOH =-log[OH^{-} ]= -log(2.3 \times 10^{-3} M) = 2.6$

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3 years ago

What is the concentration of H+ in a 2.5 M HCl solution?

Pavel [41]

Answer:

The concentration of H⁺ in a 2.5 M HCl solution is 2.5 M

Explanation:

As HCl is a strong acid and hence a strong electrolyte, it will dissociate as

HCl ⟶ H⁺ + Cl⁻

So, The concentration of H⁺ will be 2.5 M (same as HCl)

Thus, The concentration of H⁺ in a 2.5 M HCl solution is 2.5 M

<u>-TheUnknownScientist</u><u> 72</u>

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3 years ago

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