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Allushta [10]
3 years ago
9

Help me out please. please

Chemistry
2 answers:
Musya8 [376]3 years ago
8 0
#1 A #b all of the above
Nana76 [90]3 years ago
6 0
I think that question 2 is all of the above. I’m not sure about Question 1. I think that it is also all of the above but I could be wrong.
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One mole of calcium ions has the same number of representative particles as which of the following? one mole of calcium nuclei o
Kruka [31]
One mole is always the same number: 6.02 * 10^ 23.

So, one mole of cars = 6.02 * 10 ^23 cars; one mole of pencils = 6.02 * 10^23 pencils; one mole of atoms = 6.02 * 10^23 atoms; one mole of molecules = 6.02 * 10^23 molecules.

So, all the options are correct: one mole of calcium ions has 6.02 * 10^23 representative particles, such as one mole of calcium nuclei and one of calcium atoms.
3 0
3 years ago
PLEASE HELP IMMEDIATE WORTH 10 POINTS
Otrada [13]

Answer:

the scientific name is Angiosperms

Explanation:

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8 0
3 years ago
Which pair of atoms has the most polar bond?<br> (1) H−Br <br> (2) H−Cl <br> (3) I−Br<br> (4) I−Cl
S_A_V [24]
For the question given above, option 2 which is H-Cl pair of atoms has the most polar bond among the four of them. 

The larger the value of the electronegativity, the greater the atom’s strength to attract a bonding pair of electrons. <span>Hydrogen has an electronegativity of 2.1, and chlorine has an electronegativity of 3.0. The electron pair that is bonding HCl together shifts toward the chlorine atom because it has a larger electronegativity value.</span>
6 0
2 years ago
Read 2 more answers
List 5 of the 8 characteristics that define something as living
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<span>Made of cells
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7 0
3 years ago
Consider a sample of a hydrocarbon (a compound consisting of only carbon and hydrogen) at 0.959 atm and 298 K. Upon combusting t
Masja [62]

Answer:

Molecular formula of hydrocarbon is: C₂H₆

Explanation:

The combusting of the hydrocarbon:

CxHy + O₂ → CO₂ + H₂O

Using gas law to obtain molar mass of the gas mixture (CO₂ + H₂O):

P/RT = n/V

Where:

P is pressure (1,208 atm)

R is gas constant (0,082 atmL/molK)

T is temperature (375 K)

n/V = 0,0393 mol/L

1,1128 g/L ÷ 0,0393 mol/L = 28,32 g/mol

Thus, average molecular weight is:

28,32 g/mol = 44,01 g/mol X + 18,02 g/mol Y

1 = X + Y

Where X is CO₂ molar percentage and Y is H₂O molar percentage.

Solving:

X = 0,397

Y = 0,603

39,7% H₂O

60,3% CO₂

With this proportion you can obtain ratio CO₂:H₂O thus:

60,3/39,7 = 1,52 So, 2 CO₂: 3H₂O

The moles of the hydrocarbon are:

PV/RT = n

P (0,959 atm)

V ( 1/5 of final volume)

T (298K)

n = 7,85x10⁻³ mol

The moles of CO₂ are:

0,0393 mol × 2 mol CO₂/ 5 mol total =0,01572.

Ratio of CO₂:CxHY =

0,01572 : 7,85x10⁻³ 2 CO₂: 1 CxHY

Doing:

1 CxHy + O₂ → 2 CO₂ + 3 H₂O

By mass balance:

1 C₂H₆ + 7/2 O₂  → 2 CO₂ + 3 H₂O

Thus, molecular formula of hydrocarbon is: <em>C₂H₆ </em>

I hope it helps!

7 0
2 years ago
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