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Kay [80]
3 years ago
13

d="TexFormula1" title="what \: is \: water \: cycle \: \: {?} " alt="what \: is \: water \: cycle \: \: {?} " align="absmiddle" class="latex-formula">
​
Physics
2 answers:
agasfer [191]3 years ago
6 0

Answer:

water cycle show the continuous movement of water with in the earth and atmosphere

Explanation:

Hope this helps :)

Galina-37 [17]3 years ago
4 0
<h3><u>❄</u><u>Question:-</u></h3><h3>What ~is ~water~cycle?</h3><h3><u>❄Answer:-</u></h3>

The water cycle is the process through which water evaporates from the earth's surface, rises into the atmosphere, cools and condenses into rain or snow in clouds, and then falls back to the surface as precipitation. Water that falls on land gathers in rivers and lakes, soil, and porous rock strata, and much of it goes back into the seas to evaporate. Water flows in and out of the system.

<h3>✄-----------------------------------</h3><h3>hope it helps...</h3><h3>have a great day!!</h3>

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Suppose we could shrink the earth without changing its mass..?At what fraction of its current radius would the free-fall acceler
Drupady [299]

Answer:

at R/\sqrt{3}

Explanation:

The free-fall acceleration at the surface of Earth is given by

g=\frac{GM}{R^2}

where

G is the gravitational constant

M is the Earth's mass

R is the Earth's radius

The formula can be rewritten as

R=\sqrt{\frac{GM}{g}} (1)

We want to shrink the Earth at a radius R' such that the acceleration of gravity becomes 3 times the present value, so

g' = 3g

Keeping the mass constant, M, and substituting into the equation, we have

3g=\frac{GM}{R'^2}

R'=\sqrt{\frac{GM}{3g}}=\frac{1}{\sqrt{3}}\sqrt{\frac{GM}{g}}=\frac{R}{\sqrt{3}}

5 0
3 years ago
Read 2 more answers
Flying insects such as bees may accumulate a small positive electric charge as they fly. In one experiment, the mean electric ch
Eduardwww [97]

Answer:

a) True

Explanation:

There are several possible explanations for this positive charge

* The explanation of the small positive charge in the plant when the bee approaches is like a defense system of the plants,

to prevent the bees from taking the pollen, but the flowers need the bees to transport the pollen for fertilization, so this possibility is not correct

* The air is conductive so the bee indexes a charge in the nearby air, this charge must be negative and this charge induced in the air induces a charge on the flower that must be positive.

When reviewing the different statements we have

a) True, it agrees with the second explanation of the phenomenon

b) False. The earth is a deposit of negative charge

c) false. If this is the case the charge should be negative

d) False. This residual charge from the other bees is quickly neutralized by the charge from the Earth.

6 0
3 years ago
What is the mathematical relationship between voltage (V), resistance (R), and current (I)? Express your answer as an equation:
Lemur [1.5K]
V=IR
I=V/R
R=V/I
these are the realations of voltage ,resistance , and current .
3 0
3 years ago
Which statement best compares potential and kinetic energy?
xenn [34]

Answer:

D

Explanation:

Because kinetic energy do have more than potential energy: kinetic energy is when a object is moving. Potential energy is when something is at rest and has no movement what so ever

8 0
3 years ago
Assume that in 2010 the United States will need 2.0×1012 watts of electric power produced by thousands of 1000 MW power plants.
Alex73 [517]

Answer:

1752.14 tonnes per year.

Explanation:

To solve this exercise it is necessary to apply the concepts related to power consumption and power production.

By conservation of energy we know that:

\dot{P} = \bar{P}

Where,

\dot{P} = Production of Power

\bar{P} = Consumption of power

Where the production of power would be,

\dot{P} = m \dot{E}\eta

Where,

m = Total mass required

\dot{E} = Energy per Kilogram

\eta =Efficiency

The problem gives us the aforementioned values under a production efficiency of 45%, that is,

\dot{P} = \bar{P}

m \dot{E}\eta = \bar{P}

Replacing the values we have,

m(8*10^13)(0.45) = 2*10^{12}

Solving for m,

m = \frac{ 2*10^{12}}{(8*10^13)(0.45)}

m = 0.0556 \frac{kg}{s}

We have the mass in kilograms and the time in seconds, we need to transform this to tons per year, then,

m = 0.556\frac{kg}{s}*(\frac{3.1536*10^7s}{1year})(\frac{1ton}{1000kg})

m = 1752.14tonnes per year.

8 0
3 years ago
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