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3 years ago

PLEASEEE HELPPP!!!

Physics

1 answer:

Alja [10]3 years ago

3 0

Given :

A mover slides a refrigerator weighing 650 N at a constant velocity across the floor a distance of 8.1 m.

The force of friction between the refrigerator and the floor is 230 N.

To Find :

How much work has been performed by the mover on the refrigerator.

Solution :

Since, refrigerator is moving with constant velocity.

So, force applied by the mover is also 230 N ( equal to force of friction ).

Now, work done in order to move the refrigerator is :

$W = Force\times distance\\\\W = 230 \times 8.1\ N\ m\\\\W = 1863\ N\ m$

Hence, this is the required solution.

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Under certain circumstances, potassium ions (K ) in a cell will move across the 8.15 nm thick cell membrane from the inside to t

Verdich [7]

Answer:

$1.288\times 10^{-20}\ J$

Increase

Explanation:

q = Charge in the potassium ion = $19e-18e$

e = Charge of electron = $1.6\times 10^{-19}\ C$

$V_2-V_1$ = Change in potential = $0-(-80.5\times 10^{-3})$

Change in electric potential is given by

$E=q(V_2-V_1)\\\Rightarrow E=(19e-18e)(0-(-80.5\times 10^{-3})\\\Rightarrow E=1.6\times 10^{-19}\times 80.5\times 10^{-3}\\\Rightarrow E=1.288\times 10^{-20}\ J$

The energy is $1.288\times 10^{-20}\ J$

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4 0

3 years ago

Ksivusya [100]

Answer:

ok so youll tell me when you have problems

4 0

2 years ago

The speed of light is about 3.00 × 10 meters per second. What is the frequency of green light that has a wavelength about 500 na

RideAnS [48]

Answer:

The frequency of the green light is $6x10^{14}Hz$

Explanation:

The visible region is part of the electromagnetic spectrum, any radiation of that electromagnetic spectrum has a speed of $3.00x10^{8}m/s$ in the vacuum.

Green light is part of the visible region. Therefore, the frequency can be determined by the following equation:

$c = \lambda \cdot \nu$ (1)

Where c is the speed of light, $\lambda$ is the wavelength and $\nu$ is the frequency.

Notice that since it is electromagnetic radiation, equation 1 can be used. Remember that light propagates in the form of an electromagnetic wave (that is a magnetic field perpendicular to an electric field).

Then, $\nu$ can be isolated from equation 1

$\nu = \frac{c}{\lambda}$ (2)