Given :
A mover slides a refrigerator weighing 650 N at a constant velocity across the floor a distance of 8.1 m.
The force of friction between the refrigerator and the floor is 230 N.
To Find :
How much work has been performed by the mover on the refrigerator.
Solution :
Since, refrigerator is moving with constant velocity.
So, force applied by the mover is also 230 N ( equal to force of friction ).
Now, work done in order to move the refrigerator is :
Hence, this is the required solution.
Explanation:
It is given that,
Mass of the ball, m = 0.06 kg
Initial speed of the ball, u = 56 m/s
Final speed of the ball, v = -34.5 m/s (opposite direction)
(a) Let J is the impulse delivered to the ball by the racquet. It is equal to the change in momentum of the object as :
J = -5.43 kg-m/s
(b) The work done by the racquet on thee ball is equal to the change in kinetic energy as :
W = -58.372 Joules
Answer:
0.0365 A
Explanation:
Data provided in the question:
Peak value of the voltage, V = 17.0 volts
Resistance of the resistor, r = 329.0 ohm
Now,
The rms current () is given by the relation as:
on substituting the respective values, in the equation, we get
or
= 0.0365 A
Hence, the rms current is 0.0365 A