Answer:
1.42 L
Explanation:
Step 1:
The following data were obtained from the question :
Molarity of KBr = 2.40 M
Mole of KBr = 3.40 moles
Volume of solution =?
Step 2:
Determination of the volume of the solution.
Molarity of solution is simply the mole of the solute per unit volume the of solution. It is given as :
Molarity = mole /Volume
Volume = mole /Molarity
Volume = 3.4/2.4
Volume = 1.42 L
Therefore, the volume of the solution is 1.42 L
<h3>Answer:</h3>
36 moles of Hydrogen
<h3>Solution:</h3>
The molecular formula of Glucose is,
C₆H₁₂O₆
As clear from molecular formula, each mole of Glucose contains 12 moles of Hydrogen atoms.
Therefore,
1 mole of C₆H₁₂O₆ contains = 12 moles of Hydrogen
So,
3.0 moles of C₆H₁₂O₆ will contain = X moles of Hydrogen
Solving for X,
X = (3.0 mol × 12 mol) ÷ 1 mol
X = 36 moles of Hydrogen
The answer is [OH⁻] = 1 x 10⁻⁸.
To find OH⁻, divide the ionic product of water by [H₃O⁺] as :
<u>OH⁻ + H₃O⁺ = H₂O</u>
<u />
- [OH⁻] = 1 x 10⁻¹⁴ / 1 x 10⁻⁶
- [OH⁻] = 1 x 10⁻⁸
For which of the following conversions does the value of the conversion factor depend upon the formula of the substance?
The answer is C
