1. c. 35
2. <span>d. 1.26 x 10^24 molecules
3. </span><span>d. 303.6 g</span>
METALS ARE MAGNETIC(and maybe metalloids)
If 10 g of NaOH is diluted to 500 ml with water then the concentration expressed in percent is 0.5 mol/L .
Calculation ,
Given mass in gram = 10 g
Number of moles = given mass /molar mass = 10 g / 40 g/mol = 0.25mole
Given volume in ml = 500 ml
Given volume in liter = 0.5 L
Putting the value of mass and volume in equation i we get concentration expressed in percent .
C = number of moles ×100/ volume in liter = 0.25mole ×100/ 0.5 L
C = 0.5 mol/L
Concentration of solution in terms of percentage can be expressed in two ways
1) percentage by mass
2) percentage by volume
Hence, for liquid solutions, concentration is expressed in terms of percentage by volume.
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K:
m=155g
M=39g/mol
n = 155g / 39g/mol ≈ 3,97mol
KNO₃:
m=122g
M=101g/mol
n = 122g/101g/mol = 1,21mol
2K + 10KNO₃ ⇒ 6K₂O + N₂
2mol : 10mol
3,97mol : 1,21mol
limiting reagent
KNO₃ is limiting reagent
Answer:
2VO + 3Fe2O3 —> V2O5 + 6FeO
Explanation:
The skeletal equation for the reaction is given below below:
VO + Fe2O3 —> V2O5 + FeO
We can balance the equation above by doing the following:
There are 2 atoms of V on the right side and 1 atom on the left side. It can be balance by putting 2 in front of VO as shown below:
2VO + Fe2O3 —> V2O5 + FeO
Now, we have a total of 5 atoms of O on the left and 6 atoms on the right side. We can balance it by putting 3 in front of Fe2O3 and 6 in front of FeO as shown below:
2VO + 3Fe2O3 —> V2O5 + 6FeO
Now, we can see that the equation is balanced
