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RUDIKE [14]
3 years ago
5

Can boron bond with lithium

Chemistry
1 answer:
bezimeni [28]3 years ago
3 0

Answer:

No, they are not able to bond.

Explanation:

Hello there!

In this case, regarding chemical bonds, it is necessary to remember that these come up when a metal is bonded with a nonmetal, or, when two nonmetals get bonded; however, even there exist a type of denominated metallic, it is not eligible for boron and lithium because they tend to stable as cations (positive) and therefore, equal charges are not eligible for bonding, thus, boron and lithium would not be able to bond.

Best regards!

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Answer:

A more reactive halogen displaces a less reactive halogen from a solution of one of its salts.

Chlorine is more reactive than bromine, thus it displaces bromine.

4 0
3 years ago
The Balmer series consists of the spectral lines from hydrogen for an electron making a transition from an excited state to the
MaRussiya [10]

Answer:

Wavelength of the first four spectral line:

\lambda_1=1216{\AA}

\lambda_2=1026{\AA}

\lambda_3=972.8{\AA}

\lambda_4=950{\AA}

Explanation:

Lman series when electron from higher shell number and jumps to 1st shell then all the possible lines is called as lyman series.

to calculate wavelength of first four spectral line:

For hydrogen Z=1;

by using rydberg equation

\frac{1}{\lambda} =RZ^2[\frac{1}{n_1^2} -\frac{1}{n_2^2} ]

1. n=2 to n=1

\frac{1}{\lambda} =RZ^2[\frac{1}{n_1^2} -\frac{1}{n_2^2} ]

\frac{1}{R} =912{\AA} =rydberg constant

\lambda=\frac{4}{3R}

\lambda_1=1216{\AA}

2. n=3 to n=1

\lambda=\frac{9}{8R}

\lambda_2=1026{\AA}

3. n=4 to n=1

\lambda=\frac{16}{15R}

\lambda_3=972.8{\AA}

4. n=5 to n=1

\lambda=\frac{25}{24R}

\lambda_4=950{\AA}

5 0
3 years ago
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3 years ago
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Some of the reactants or the products are in the gaseous phase.
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4 years ago
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