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RUDIKE [14]
3 years ago
5

Can boron bond with lithium

Chemistry
1 answer:
bezimeni [28]3 years ago
3 0

Answer:

No, they are not able to bond.

Explanation:

Hello there!

In this case, regarding chemical bonds, it is necessary to remember that these come up when a metal is bonded with a nonmetal, or, when two nonmetals get bonded; however, even there exist a type of denominated metallic, it is not eligible for boron and lithium because they tend to stable as cations (positive) and therefore, equal charges are not eligible for bonding, thus, boron and lithium would not be able to bond.

Best regards!

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ZanzabumX [31]

Answer:

= 74.4 grams / mole. Ernest Z. The reaction will produce 15.3 g of KCl

Explanation:

4 0
2 years ago
What is the pressure in a gas container that is connected to an open-end U-tube manometer if the pressure of the atmosphere is 7
Whitepunk [10]

Answer:

The pressure in the gas is 656mmHg

Explanation:

In calculating the pressure of the gas;

step 1: convert the height of the mercury arm to mmHg

9.60cm = 96.0 mmHg

step 2: convert 752 torr to mmHg

I torr is 1 mmHg

752 torr = 752mmHg

Step 3: since the level of mercury in the container is higher than the level of mercury exposed to the atmosphere, we substrate the values to obtain our pressure.

So, 752mmHg - 96mmHg = 656mmHg

The pressure in the gas container is therefore 656mmHg.

N. B : if the mercury arm is in lower position, you add.

5 0
3 years ago
to form brass, copper and zinc combine but do not chemically bond. brass is a(n) ________. a atom b element c compound d
umka21 [38]

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3 0
2 years ago
What chemical process occurs in cells to release energy?
Lana71 [14]

Answer:

B. Respiration

Explanation:

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formula:

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3 0
2 years ago
What is the pH of pure water at 40.0°C if the Kw at this temperature is 2.92 - 10-147 OA) 6.767 O B) 0 465 O c) 7.000 OD) 7 233
Sergeeva-Olga [200]

Answer:

PH= 6.767     (answer is the A option)

Explanation:

first we need to correct the value in Kw at this temperature is 2.92*10^-14

so, in this case we have that:

Kw=2.92*10^-14 M²

[ H3O^+] [ H3O^+]

[H_{3}O^{+}  ] [OH^{-}  ] = Kw = 2.92*10^{-14} M^{2}   \\\\

at 40ºC

[H_{3}O^{+}  ] = [OH^{-}  ]

[H_{3}O^{+}  ]^{2} = 2.92*10^{-14} M^{2}

[H_{3}O^{+}  ] = (2.92*10^{-14})^{1/2} = 1.71*10^{-7} M

PH= -log10[H_{3}O^{+}  ] = -log10(1.71*10^{-7} ) = 6.767

7 0
2 years ago
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