Give a quantitative definition of being in contact.
1 answer:
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We can use the kinematic equation
where Vf is what we are looking for
Vi is 0 since we start from rest
a is acceleration
and d is the distance
we get
(Vf)^2 = (0)^2 + 2*(2)*(500)
(Vf)^2 = 2000
Vf = about 44.721
or 44.7 m/s [if you are rounding this by significant figures]
where Vf is what we are looking for
Vi is 0 since we start from rest
a is acceleration
and d is the distance
we get
(Vf)^2 = (0)^2 + 2*(2)*(500)
(Vf)^2 = 2000
Vf = about 44.721
or 44.7 m/s [if you are rounding this by significant figures]
Note: I assume the mirror is concave, so that its focal length is positive (it is not specified in the text)
1a) We can use the mirror equation to find the distance of the image from the mirror:
where
is the focal length
is the distance of the object from the mirror
is the distance of the image from the mirror.
Rearranging the equation, we find
so, the distance of the image from the mirror is
.
1b) The image height is given by the magnification equation:
where
is the heigth of the image and 
is the height of the object. By rearranging the equation and using p and q, we find
and the negative sign means the image is inverted.
2) As before, we can find the distance of the image from the mirror by using the mirror equation:
Rearranging it, we find
so, the distance of the image from the mirror is
3) As before, we find the distance of the image from the mirror by using the mirror equation:
Rearranging it, we find
so, the distance of the image from the mirror is
And now we can use the magnification equation to find the image height:
Rearranging it, we find
and the negative sign means the image is inverted.
1a) We can use the mirror equation to find the distance of the image from the mirror:
where
Rearranging the equation, we find
so, the distance of the image from the mirror is
1b) The image height is given by the magnification equation:
where
and the negative sign means the image is inverted.
2) As before, we can find the distance of the image from the mirror by using the mirror equation:
Rearranging it, we find
so, the distance of the image from the mirror is
3) As before, we find the distance of the image from the mirror by using the mirror equation:
Rearranging it, we find
so, the distance of the image from the mirror is
And now we can use the magnification equation to find the image height:
Rearranging it, we find
and the negative sign means the image is inverted.