The volume of 1.0 g of nitrogen in a balloon is increased. It causes: the mass of the gas to decrease the density of the gas to increase and the pressure of the gas to decrease the temperature of the gas decrease.
<h3>What is volume?</h3>
How much space an object or substance takes up.
If you increase the temperature of the gas in the balloon, the pressure will initially increase. The balloon will expand until the pressure inside drops back down and is equal to the pressure outside.
If you increase the atmospheric pressure, the balloon will compress until the pressure inside equals the new pressure outside.
If you remove gas from the balloon, the pressure will drop, causing the balloon to compress until the pressure is again equal to the pressure outside.
if you place the balloon underwater, it will be under greater pressure, causing the balloon to compress until the inside pressure equals the new outside pressure.
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Balanced chemical reaction: 2HI(aq) + Ba(OH)₂(aq) → BaI₂(aq) + 2H₂O(l).
Ionic reaction: 2H⁺ + I⁻(aq) + Ba²⁺ + 2OH⁻(aq) → Ba²⁺ + 2I⁻(aq) + 2H₂O(l).
Net ionic reaction: 2H⁺ + 2OH⁻(aq) → 2H₂O(l).
Barium iodide is salt that dissolves in water, barium hydroxide is strong base that dissolves in water.
This is example of double replacement reactions(double displacement or metathesis reactions), two ionic compounds are exchanged, making two new compounds
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With that informatio you can:
1) Write the chemical equation
2) Balance the chemical equation
3) State the molar ratios
4) Predict if precipitation occurs.
I will do all four, for you:
1) Chemical equation:
mercury(I) nitrate potassium bromide mercury(I) bromide potassium nitrate
<span>Hg2(NO3)2 + KBr → Hg2Br2 + KNO<span>3
2) Balanced chemical equation
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<span>Hg2(NO3)2 + 2KBr → Hg2Br2 + 2KNO<span>3
3) Molar ratios or proportions:
1 mol </span></span><span>Hg2(NO3)2 : 2 mol KBr : 1 mol Hg2Br2 : 2 mol KNO<span>3
4) Prediction of precipitation.
You can use the solubility rules or a table of solubilities. I found in a table of solutiblities that mercury(I) bromide is insoluble and potassium bromide is soluble, Then you can predict that the precipitation of mercury(I) bromide will occur.
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I uploaded the answer to a file hosting. Here's link:
tinyurl.com/wpazsebu
When you assume that the gas is behaving ideally, the gas molecules are very far from each other that they do not have any intermolecular forces. If it behaves this way, you can assume the ideal gas equation:
PV = nRT, where
P is the pressure
V is the volume
n is the number of moles
R is a gas constant
T is the absolute temperature
When the process goes under constant pressure (and assuming same number of moles),
P/nR = T/V = constant, therefore,
T₁/V₁=T₂/V₂
If V₂ = V₁(1+0.8) = 1.8V₁, then,
T₂/T₁ = 1.8V₁/V₁
Cancelling V₁,
T₂/300=1.8
T₂ =540 K
If you do not assume ideal gas, you use the compressibility factor, z. The gas equation would now become
PV =znRT
However, we cannot solve this because we don't know the value of z₁ and z₂. There will be more unknowns than given so we won't be able to solve the problem. But definitely, the compressibility factor method is more accurate because it does not assume ideality.
