Answer:
Magnetic flux through the loop is 1.03 T m²
Explanation:
Given:
Magnetic field, B = 4.35 T
Radius of the circular loop, r = 0.280 m
Angle between circular loop and magnetic field, θ = 15.1⁰
Magnetic flux is determine by the relation:
....(1)
Here A represents area of the circular loop.
Area of circular loop, A = πr²
Hence, the equation (1) becomes:
Substitute the suitable values in the above equation.
= 1.03 T m²
The answer for the following problem is explained below.
Therefore the volume charge density of a substance (ρ) is 0.04 × C.
Explanation:
Given:
radius (r) =2.1 cm = 2.1 × m
height (h) =8.8 cm = 8.8 × m
total charge (q) =6.1× C
To solve:
volume charge density (ρ)
We know;
<u> ρ =q ÷ v</u>
volume of cylinder = π ×r × r × h
volume of cylinder =3.14 × 2.1 × 2.1 × × 8.8 ×
volume of cylinder (v) = 122.23 ×
<u> ρ =q ÷ v</u>
ρ = 6.1× ÷ 122.23 ×
<u>ρ = 0.04 × </u><u> C</u>
Therefore the volume charge density of a substance (ρ) is 0.04 × C.
Answer:
The value is
Explanation:
From the question we are told that
The operating temperature is
The emissivity is
The power rating is
Generally the area is mathematically represented as
Where is the Stefan Boltzmann constant with value
So