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Vika [28.1K]
4 years ago
10

Write down the equation, in words, for the formation of rust.

Physics
1 answer:
Free_Kalibri [48]4 years ago
8 0

Answer:

Fe2O3

Explanation:

The chemical formula for rust is Fe2O3. Rust is formed when iron reacts with oxygen in moist air. The following chemical equation represents the reaction: 4Fe + 3O2 → 2Fe2O3. Water is necessary for the oxidation reaction to occur and to facilitate transport of the electrons.

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I believe its the second oneee

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3 years ago
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An artillery shell is fired at a target 200 m above the ground. When the shell is 100 m in the air, it has a speed of 100 m/s. W
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Explanation:

Below is an attachment containing the solution.

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3 years ago
Ethan pushes a wooden box across a carpeted floor. Then he pushes the same box across a smooth marble floor. Why does Ethan find
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Answer:

B.The box experiences less friction on the marble floor

Explanation:

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A 2.2 kg box is sliding along a frictionless horizontal surface with a speed of 1.8 m/s when it encounters a spring. (a) Determi
iogann1982 [59]

Answer:

a) k = 2851.2\,\frac{N}{m}, b) v = 0.54\,\frac{m}{s}

Explanation:

a) According to the Principle of Energy Conservation, the kinetic energy of the box is transformed into elastic potential energy.

\frac{1}{2}\cdot (2.2\,kg)\cdot (1.8\,\frac{m}{s} )^{2} = \frac{1}{2}\cdot k \cdot (0.05\,m)^{2}

The spring constant is:

k = 2851.2\,\frac{N}{m}

b) The initial speed needed to compress the spring by 1.5 centimeters is:

\frac{1}{2}\cdot (2.2\,kg)\cdot v^{2} = \frac{1}{2}\cdot (2851.2\,\frac{N}{m} )\cdot (0.015\,m)^{2}

v = 0.54\,\frac{m}{s}

5 0
4 years ago
A small block is released from rest from the edge of a large hemispherical frictionless bowl with radius 3 m. As the mass passes
andreyandreev [35.5K]

Explanation:

It is given that,

Radius of bowl, r = 3 m

A small block is released from rest from the edge of a large hemispherical friction less bowl. Let v is the speed of the mass when it passes through the bottom of the bowl and u is the initial speed of the  mass, u = 0. Using conservation of energy as :

mgh=\dfrac{1}{2}mv^2

h = r = 3 m

v=\sqrt{2gh}

v=\sqrt{2\times 9.8\ m/s^2\times 3\ m}

v = 7.66 m/s

or

v = 7.7 m/s

So, the speed of the mass at the bottom of the bowl is 7.7 m/s. Hence, this is the required solution.

4 0
3 years ago
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