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slava [35]
3 years ago
10

How large is the Milky Way Galaxy? A. It is the largest galaxy ever observed. B. It takes up over half of the known universe. C.

It cannot be measured or compared. D. It is very small when compared to the universe
Physics
1 answer:
lisabon 2012 [21]3 years ago
4 0

Answer:

D. It is very small when compared to the universe

Explanation:

The Milky Way can be regarded galaxy which has Solar System in it. Milky way gives the description of appearance of galaxy from Earth, it is a hazy band of light that's been formed from the stars which can be visualized in the sky during the night, though it cannot be sorted by mere human eyes. Milky Way has existed for about 13.51 billion years with the radius of 52,850 light years. the Number of stars in milky way is about 100-400 billion. It should be noted that themilky way galaxy is a very large galaxy but It is very small when compared to the universe

.

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Amplitude modulation is used in?
melamori03 [73]

Amplitude modulation is used in AM radio.

Answer is A.

8 0
4 years ago
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Enumerar 5 actividades en casa o en el trabajo en la que usualmente se mantenga una postura corporal incorrecta
ludmilkaskok [199]

Answer:

Existen cinco actividades en las que se mantiene una postura corporal incorrecta:

1) Sentarse en una silla.

2) Agacharse y levantar una objeto del piso, especialmente cuando es pesado.

3) Sentarse en un escritorio, especialmente frente a una computadora.

4) Llevar una mochila, especialmente si está sobrecargada.

5) Dormir sobre una cama en una posición inadecuada.

Explanation:

Existen cinco actividades en las que se mantiene una postura corporal incorrecta:

1) Sentarse en una silla.

2) Agacharse y levantar una objeto del piso, especialmente cuando es pesado.

3) Sentarse en un escritorio, especialmente frente a una computadora.

4) Llevar una mochila, especialmente si está sobrecargada.

5) Dormir sobre una cama en una posición inadecuada.

5 0
3 years ago
How does increasing the tension of a spring affect a wave on the spring?
umka21 [38]

When waves travel across strings, the larger the tension of the string the faster the velocity of the wave. This is because of the equation:

v = the square root of (T/(m/L)) where T is the tension, m the mass of the string, and L the length of the string

Hope this helps!


5 0
3 years ago
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When an object is fully converted into energy the amount of energy liberated is
EleoNora [17]

Answer:

Mass, m = 4 kg

Explanation:

<u>Given the following data;</u>

Energy = 3.6 * 10^17 Joules

We know that the speed of light is equal to 3 * 10⁸ m/s.

To find the mass of the substance;

The theory of special relativity by Albert Einstein gave birth to one of the most famous equation in science.

The equation illustrates, energy equals mass multiplied by the square of the speed of light.

Mathematically, the theory of special relativity is given by the formula;

E = mc^{2}

Where;

  • E is the energy possessed by a substance.
  • m is the mass.
  • c is the speed of light.

Substituting into the formula, we have;

3.6 * 10^{17} = m * 300000000^{2}

3.6 * 10^{17} = m * 9*10^{16}

m = \frac {3.6 * 10^{17}}{9*10^{16}}

Mass, m = 4 kg

8 0
3 years ago
Two wires with equal lengths are made of pure copper. The diameter of wire A is three times the diameter of wire B. When 8 kg ma
noname [10]

Answer: c. YA < YB

Explanation:

The formula for Young’s modulus is = Tensile stress / Tensile strain

Tensile stress = Force x Length

Force = mass x acceleration due to gravity

 = 8kg x 10m/s

 = 80kgm/s

Tensile stress  = 80kgm/s x 2m = 160kgm2/s

Tensile strain = Area x change in length

Area = pi x D2 / 4 ; Pi = 3.14

Change in length = L2 – L1 (New length – Initial length)

Given parameters:

Length of wire A = Length of wire B, (let’s use 2meters for the calculation)

For wire A, Diameter = 3 x Wire B diameter

Assuming Diameter of wire B = 1meter

Therefore, diameter of wire A = 1 x 3 = 3meters

It is said that wire B stretches more than wire A when the man of 8kg is placed on both

For wire B, let’s assume new length is = 4m

For wire A let’s assume new length is = 3m.

(i) Tensile strain of wire A =  

Area of wire A = 3.14 x (32)/4 = 7.065m2

Change in length = 3m - 2m = 1m.

Therefore, tensile strain = 7.065m2 x 1m = 7.065m3

Young’s modulus for wire A (YA) = 160kgm2/s divided by 7.065m3  

   = 22.64Pa.

(ii) Tensile strain of wire B =

Area of wire B = 3.14 x (12)/4 = 0.785m2

Change in length = 4m – 2m = 2m

Therefore, tensile strain = 0.785m2 x 2m = 1.57m3

Young’s modulus for wire B (YB) = 160kgm2/s divided by 1.57m3

   = 101.91Pa.

From the calculations above, we see that YA is less than YB (YA < YB). This is true given that wire A has a greater diameter than wire B which in turn impacts the Area of the wire since the diameter is directly proportional to area and the area is inversely proportional to the young’s modulus.

5 0
3 years ago
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