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suter [353]
3 years ago
13

Describe the shapes and relative energies of the s, p, d, and f atomic orbitals. (3 points) Be sure you address both the shapes

of each atomic orbital and the relative energy for each orbital. Be sure to use ACE format to answer this question. This type of problem came from unit 3.
Chemistry
1 answer:
Makovka662 [10]3 years ago
6 0

Answer:

According to the subshells, the  ns subshell has a sphere-like shape, and on average, lower energy than the rest of the subshells on the same quantum level  

The np subshell has two lobes opposite the origin, and on average has more energy than a ns subshell since it has one more angular node, and thus  np electrons are less core-like (and further away from the nucleus).

n d orbitals have five spatial orientations:

and n f orbitals have seven spatial orientations

The energies are on average in increasing order for the same energy level , n as follows,

nS < nP < nD < nF

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Answer:

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Why does a star expand into a red giant?​
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Answer:

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2 years ago
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Answer:  See below

Explanation:  a.  The mass of an element is composed of:

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neutrons:   1 amu each

electrons:   0 amu each

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If 1.16 L of water is initially at 24.2 ∘C, what will its temperature be after absorption of 9.4×10−2 kWh of heat?
vitfil [10]

Answer:

The temperature will be 93.92 °C

Explanation:

To explain this we will use following equation: also  Q = ∆U + W known as the NON-FLOW ENERGY EQUATION (N.F.E.E.)

With Q = heat added to the system

with ∆U  = change in internal energy

⇒∆U = ( m )( Cv )( T2 - T1 )

With W = work done by the system

⇒For this situation W = 0 because there isn't work done

So we get: ∆U = ( m )( Cv )( T2 - T1 ) = Q

To find the temperature, we have to isolate T in the equation:

(T2-T1) = Q / (m)(Cv)

⇒ Since we know that m = density * volume we can calculate the mass of water.

mass = 1000g/L * 1.16 L = 1160g

Cv = heat capacity ⇒ water has a  heat capacity of 4.184 J/g °C

We know the absorption of heat is 9.4x 10^-2 kWh but to know how many joule this is we should convert ( 1 joule = 3.6 x 10^6 kWh)

⇒Q = ( 0.094 kWh ) ( 3.6 x 10^6 J / kWh ) = 0.3384 x 10^6 J

For the temperature we get then: T2 -T1 = Q / (m)(Cv)

T2 - T1 =  0.3384 x 10^6 J / (( 1160g)*(4.184 J/g °C)) = 69.72 ° C

T2 = ( T2 - T1 ) + T1   ⇒ 69.72 + 24.2 = 93.92 °C

6 0
3 years ago
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