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suter [353]
3 years ago
13

Describe the shapes and relative energies of the s, p, d, and f atomic orbitals. (3 points) Be sure you address both the shapes

of each atomic orbital and the relative energy for each orbital. Be sure to use ACE format to answer this question. This type of problem came from unit 3.
Chemistry
1 answer:
Makovka662 [10]3 years ago
6 0

Answer:

According to the subshells, the  ns subshell has a sphere-like shape, and on average, lower energy than the rest of the subshells on the same quantum level  

The np subshell has two lobes opposite the origin, and on average has more energy than a ns subshell since it has one more angular node, and thus  np electrons are less core-like (and further away from the nucleus).

n d orbitals have five spatial orientations:

and n f orbitals have seven spatial orientations

The energies are on average in increasing order for the same energy level , n as follows,

nS < nP < nD < nF

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______ is the type of heat that roasts the marshmallows.
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Aluminum reacts with a certain nonmetallic element to form a compound with the general formula AIX; where element X is a diatomi
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6 0
3 years ago
When a 12.8 g sample of KCL dissolves in 75.0 g of water in a calorimeter the temp. drops from 31 Celsius to 21.6 Celsius. Calcu
Delicious77 [7]

Answer:

Step 1: Calculate qsur (the surrounding is

usually the water)

qsur = ? J

m = 75.0 g water

c = 4.184 J/g

oC

ΔT = (Tfinal- Tinitial)= (21.6 – 31.0) = -9.4 oC

qsur = m · c · (ΔT)

qsur = (75.0g) (4.184 J/g

oC) (-9.4 oC)

qsur = - 2949.72 J

First, using the information we know that we

must solve for qsur, which is the water. We know

the mass for water, 75.0g, the specific heat of

the water, 4.184 j/g

o

c, and the change in

temperature, 21.6-31.0 = -9.4 oC. Plugging it

into the equation, we solve for qsur.

Step 2: Calculate qsys qsys = - (qsur)

qsys = - (- 2949.72 J)

qsys = + 2949.72

In this case, the qsur is negative, which means

that the water lost energy. Where did it go? It

went to the system. Thus, the energy of the

system is negative, opposite, the energy of the

surrounding.

Step 3: Calculate moles of the substance

that is the system

Given: 12.8 g KCl

Mol system = (g system given)

(molar mass of system)

Mol system = (12.8 g KCl)

(39.10g + 35.45g)

Mol system = 12.8 g KCl

74.55 g

Mol system = 0.172

Here, we solve for the mol in the system by

using the molar mass of the material in the

system.

Step 4: Calculate ΔH ΔH = q sys .

Mol system

ΔH= + 2949.72 J

0.172 mol

ΔH= +17179.81 J/mol or +1.72 x 104

J/mol

i hope this helps

7 0
4 years ago
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