Ask question

Ask question

All categories

2 years ago

11

What is the difference between atmosphere and atmospheric pressure?

2 answers:

agasfer [191]2 years ago

8 0

Atmosphere is a layer around the earth and atmospheric pressure is the pressure exerted by the atmosphere also called air air pressure.

hope this helped!

jeka57 [31]2 years ago

7 0

Answer:

That pressure is called atmospheric pressure, or air pressure. It is the force exerted on a surface by the air above it as gravity pulls it to Earth. Atmospheric pressure is commonly measured with a barometer. ... One atmosphere is 1,013 millibars, or 760 millimeters (29.92 inches) of mercury.

Explanation:

You might be interested in

The population of the Earth at the end of 2018 was approximately 7.7 × 10 9 people. Which of the following is the correct way of

stepladder [879]

Answer:

7700000000

Explanation:

so 7.7 x 10 to the power of 9 is in standard form

to put it into a number you just need to times it by 1000000000

however your answer will only have 8 zeros because of the decimal point

5 0

3 years ago

Determine what’s wrong with these electronic configurations

Anika [276]

Answer:

Explanation:

19) it is 3d10 instead of 4d10

20) it is missing 3p6, and 4s2 before 3d5

21) Ra is not a noble gas

22) Cs is not a noble gas

7 0

2 years ago

How much heat will be given off when 1500 g of water cools down by 20 C? please help and explain:)))

docker41 [41]

Answer:

126000J

Explanation:

From the question given, we obtained the following information:

M = 1500g

C = 4.2J/g°C

ΔT = 20°C

Q =?

Q= MCΔT

Q = 1500 x 4.2 x 20 =

Q = 126000J

7 0

3 years ago

The radioactive isotope of lead, Pb-209, decays at a rate proportional to the amount present at time t and has a half-life of 3.

Marina86 [1]

Answer:

Therefore it will take 7.66 hours for 80% of the lead decay.

Explanation:

The differential equation for decay is

$\frac{dA}{dt}= kA$

$\Rightarrow \frac{dA}{A}=kdt$

Integrating both sides

ln A= kt+c₁

$\Rightarrow A= e^{kt+c_1}$

$\Rightarrow A=Ce^{kt}$ [ $e^{c_1}=C$ ]

The initial condition is A(0)= A₀,

$\therefore A_0=Ce^{0.k}$

$\Rightarrow C=A_0$

$\therefore A=A_0e^{kt}$ .........(1)

Given that the $Pb_{209}$ has half life of 3.3 hours.

For half life $A=\frac12 A_0$ putting this in equation (1)

$\frac12A_0=A_0e^{k\times3.3}$

$\Rightarrow ln(\frac12)= 3.3k$ [taking ln both sides, $ln \ e^a=a$ ]

$\Rightarrow k=\frac{ln \frac12}{3.3}$

⇒k= - 0.21

Now A₀= 1 gram, 80%=0.8

and A= (1-0.8)A₀ = (0.2×1) gram = 0.2 gram

Now putting the value of k,A and A₀in the equation (1)

$\therefore 0.2=1e^{(-0.21)\times t}$

$\Rightarrow e^{-0.21t}=0.2$

$\Rightarrow -0.21t= ln(0. 2)$

$\Rightarrow t= \frac{ln (0.2)}{-0.21}$

⇒ t≈7.66

Therefore it will take 7.66 hours for 80% of the lead decay.

3 0

2 years ago

Where does the classification of species fall?

ivolga24 [154]

Explanation:

develop a short message which you will deliver to the people in this community about application of chemistry in everyday life

5 0

1 year ago