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3241004551 [841]
3 years ago
8

When you drop a paper clip, why doesn't it fall toward you instead of toward Earth?

Physics
1 answer:
svetoff [14.1K]3 years ago
5 0
Because gravity has been known to define as a force of attraction between things that have mass.
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How is a light wave likely to react when hitting a shiny opaque object?
shepuryov [24]

Answer:

b

Explanation:

The light wave will be reflected

6 0
3 years ago
A man on the moon with a mass of 90 kilograms weighs 146 newtons. The radius of the moon is 1.74 × 106
ehidna [41]
The formula is F=k\frac{mm_0}{r^2}, where k is the universal constant of gravity, m the mass of the moon, m_0 that of the man and r the radius of the moon. Solve for m.
6 0
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How much heat is absorbed by a 47g iron skillet when its temperature rises from 12oC to 20oC?
jolli1 [7]

Answer

169.2 J

Explanation

Given in the question,

mass of iron = 47g

specific heat capacity of iron = 0.450 (J/g 0C)

initial temperature = 12° C

final temperature = 20° C

The energy q needed to increase an object of mass m and specific heat capacity c by a temperature θ is given by:

q = mcΔt

q = 47(0.45)(20-12)

q = 169.2 J

6 0
3 years ago
What is the evaluation?
natita [175]
These are listed on the map, but A & B are 900', C is 1500', and D is 1000'
7 0
3 years ago
The speed of a wave on a violin A string is 288 m/s and on the G string is 128 m/s. The force exerted on the ends of the string
Katyanochek1 [597]

Answer:

\dfrac{\mu_A}{\mu_G}=0.197

Explanation:

given,

Speed of a wave on violin A = 288 m/s

Speed on the G string = 128 m/s

Force at the end of string G  = 110 N

Force at the end of string A = 350 N

the ratio of mass per unit length of the strings (A/G). = ?

speed for string A

 v_A = \sqrt{\dfrac{F_A}{\mu_A}}.......(1)

speed for string G

 v_G = \sqrt{\dfrac{F_G}{\mu_G}}........(2)

Assuming force is same in both the string

now,

dividing equation (2)/(1)

\dfrac{v_G}{v_A}=\dfrac{\sqrt{\dfrac{F_G}{\mu_G}}}{\sqrt{\dfrac{F_A}{\mu_A}}}

\dfrac{v_G}{v_A}=\dfrac{\sqrt{\mu_A}}{\sqrt{\mu_G}}

\dfrac{128}{288}=\dfrac{\sqrt{\mu_A}}{\sqrt{\mu_G}}

\dfrac{\mu_A}{\mu_G}=0.197

5 0
3 years ago
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