S=125km
t=2h
v=s/t=125/2=62,5km/h
or 62,5/3,6=17,36m/s
The solution for this problem is through this formula:Ø = w1 t + 1/2 ã t^2
where:Ø - angular displacement w1 - initial angular velocity t - time ã - angular acceleration
128 = w1 x 4 + ½ x 4.5 x 5^2 128 = 4w1 + 56.254w1 = -128 + 56.25 4w1 = 71.75w1 = 71.75/4
w1 = 17.94 or 18 rad s^-1
w1 = wo + ãt
w1 - final angular velocity
wo - initial angular velocity
18 = 0 + 4.5t t = 4 s
Answer:
H = 6.93 m
Explanation:
given data
velocity v = 35 m/s
horizontal component Vx = 33 m/s
solution
we get here maximum height so first we get vertical component here that is express as
Vy = 
.........................1
put here value
Vy = 
Vy = 11.66 m/s
and
now we get height
H = 
.............................2
put here value
H = 
H = 6.93 m
Answer: the earth
Explanation: ask your teacher
Answer:
Behaves as a wave.
Explanation:
The dual nature of light means that light behaves as a wave. If the light consisted of small particles, the alternating light and dark bands would not have occurred.
Sometimes it behaves like a particle (called a photon), which explains how light travels in straight lines.
