Answer:
See explanation
Explanation:
The reaction of a benzyl bromide with a nucleophile may proceed by SN1 or SN2 mechanism depending on the nature of the solvent used.
Since SN1 reaction involves the formation of a carbocation, it usually predominates in the presence of a poor nucleophiles and protic solvents. Hence when methanol is used as solvent and a poor nucleophile is used, SN1 mechanism predominates.
However, when acetone which is an aprotic solvent is used in the presence of a good nucleophile, SN2 reaction mechanism predominates.
Answer:
0.54 mole
Explanation:
CH3COOH CH3CH2OH CH3COOCH2CH3 H2O
Initial concentration 1.0 mole 1.0 mole 0 mole 1.0mol
Change - x - x + x + x
Equilibrium (1.0 - x) (1.0 - x) x (1.0 + x)
K = [CH3COOCH2CH3]*[H2O]/[CH3COOH]*[CH3CH2OH]
x*(1.0+x)/(1.0-x)(1.0-x) = 4.0
x+x²=4*(1-x)²
x+x² = 4(1² - 2x + x²)
x + x² = 4 - 8x + 4x²
4 - 8x + 4x²- x² - x= 0
3x² - 9x + 4 = 0
x=2.5 , x=0.54
2.5 mole of acid cannot be esterified, because there is only 1.0 mole of acid,
so answer is 0.54 mole.
Answer:
MgCl2 - 6H2O
203.3 mol
MgCl2 + 2Na = 2NaCl + Mg
22.6g
Explanation:
1. Write the formula of hydrate and find molar mass.
2. Write a balanced single replacement (don't include H2O)
3. Do the given/wanted calculation (include H2O in molar mass of given)
1. Which of the following is not true of a covalent compound?
<span>It is made of only nonmetals.
</span><span>2. What type of compound is almost always found as a solid?
</span>Ionic compound is almost always found as a solid because they have very tightly bound structures.
<span>3. Which of the following is not a characteristic of an ionic compound?
</span><span>It is formed when atoms share electrons.
</span>4. Covalent compounds are formed when
<span>a nonmetal bonds with a nonmetal.
</span><span>5. What is the relationship between a compound and the elements it is made from?
</span>The compound may have properties that are very different from those of the elements.
Answer:
See explanation
Explanation:
Racemization is said to occur when a 1:1 ratio of (+) and (-) enantiomers of a compound are produced in a reaction.
The reaction of optically active (R)-2-methylcyclohexanone with either aqueous base or acid leads to the formation of a planar enol species for reaction with acid and a planar enolate species for reaction with base.
Both reactions involves the formation of achiral species which reverts back to the chiral product with equal chances of the formation of both enantiomers of the product during the process. This leads to racemization of the product in both cases.
