Answer:
The supplement angle 140° angle.
Step-by-step explanation:
Answer:
Step-by-step explanation:
Volume of the figure = Volume of cone + Volume of hemisphere
Cone:
height h = 33 m
Diameter = 30m
Radius r = 30/2 = 15 m
Volume of Cone:

Hemisphere:
Radius r = 15 m
Volume of Hemisphere =

Volume of the figure = 2475π + 2250π = 4725π m²
Answer:
The probability that the average length of rods in a randomly selected bundle of steel rods is greater than 259 cm is 0.65173.
Step-by-step explanation:
We are given that a company produces steel rods. The lengths of the steel rods are normally distributed with a mean of 259.2 cm and a standard deviation of 2.1 cm. For shipment, 17 steel rods are bundled together.
Let
= <u><em>the average length of rods in a randomly selected bundle of steel rods</em></u>
The z-score probability distribution for the sample mean is given by;
Z =
~ N(0,1)
where,
= population mean length of rods = 259.2 cm
= standard deviaton = 2.1 cm
n = sample of steel rods = 17
Now, the probability that the average length of rods in a randomly selected bundle of steel rods is greater than 259 cm is given by = P(
> 259 cm)
P(
> 259 cm) = P(
>
) = P(Z > -0.39) = P(Z < 0.39)
= <u>0.65173</u>
The above probability is calculated by looking at the value of x = 0.39 in the z table which has an area of 0.65173.
74-2=72 and 72 times 3=216 that willl be your answer
Answer:
A
Step-by-step explanation:
in option B, you are adding the 3 pound plastic box to each cardboard box
in option A, you have 5 separate carboard packages, and one 3 pound plastic box
This [option a] is the diagram that matches the scenario given.
Think of the x's as normal numbers. Let's say the weight of each "x" is 1. [it's not I'm aware that this question is different]
if you have 5 x's, you have
1 1 1 1 1 3
<em>not </em>1+3 ; 1+3 ; 1+3 ; 1+3 ; 1+3
you would only have this if you were to add a 3 pound plastic box to each individual package