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Drupady [299]
3 years ago
15

A glucose solution that is prepared for a patient should have a concentration of 180 g/L. A nurse has 18 g of glucose. How many

liters of water should she add to the glucose to obtain the required solution?
Chemistry
2 answers:
Anuta_ua [19.1K]3 years ago
6 0
You start by using proportions to find the number of liters of solution:

180 g of glucose / 1 liter of solution = 18 g of glucose / x liter of solution


=> x = 18 g of glucose * 1 liter of solution / 180 g of glucose = 0.1 liter of solution.


If you assume that the 18 grams of glucose does not apport volume to the solution but that the volume of the solution is the same volumen of water added (which is the best assumption you can do given that you do not know the how much the 18 g of glucose affect the volume of the solution) then you should add 0.1 liter of water.

Answer: 0.1 liter of water.

 
uranmaximum [27]3 years ago
4 0

Answer:

0.10 L

Explanation:

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How do scientists collect evidence to form a valid theory about the formation and early development of the solar system?
lys-0071 [83]

Scientists collected evidence to form a valid theory about the formation and early development of the solar system include:

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<h3>What is Solar system?</h3>

This is referred to the gravitationally bound system of the Sun and the objects that orbit it.

It also comprises of the planets and their moons and objects such as asteroids and the evidence which shows that the formation of the solar system are the gas and dust which form the stars and debris found around them.

This therefore makes it the evidence collected in the formation of the solar system mentioned the most appropriate choice.

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5 0
2 years ago
A cylindrical rod has a length of 27 cm and a diameter of 1.6 mm. What is the cross-sectional area in 10-6 m2?
MrRa [10]

<u>Answer:</u> The cross-sectional area of the cylindrical rod is 2.01\times 10^{-6}m^2

<u>Explanation:</u>

We are given a cylindrical rod whose cross-sectional area will be in the form of circle.

To calculate the area of circle, we use the equation:

\text{Area}=\pi r^2

where,

r = radius of the rod = \frac{d}{2}=\frac{1.6mm}{2}=0.8mm=0.8\times 10^{-3}m    (Conversion factor: 1 m = 1000 mm)

Putting values in above equation, we get:

\text{Area}=3.14\times (0.8\times 10^{-3})^2\\\\\text{Area}=2.01\times 10^{-6}m^2

Hence, the cross-sectional area of the cylindrical rod is 2.01\times 10^{-6}m^2

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