2 years ago

People can hear ultrasound easily. A. True B. False

1 answer:

3 0

Ultrasound is sound waves with frequencies higher than the upper audible limit of human hearing. Ultrasound is not different from "normal" (audible) sound in its physical properties, except that humans cannot hear it. ... Ultrasound is used in many different fields.

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You have a hard glass flask that you plug up with a stopper at room temperature (25 C) and an internal pressure of 1 atm. If you

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Answer:

pressure of 0atm

Explanation:

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3 years ago

Calculate the net change in enthalpy for the formation of one mole of acrylic acid from calcium carbide, water and carbon dioxid

Zielflug [23.3K]

Check the attached file for the answer.

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3 years ago

You combine 13 g of magnesium with 5 g of nitrogen to form a compound.

guapka [62]

Answer:

$\large \boxed{28 \, \% }$

Explanation:

magnesium + nitrogen ⟶ Product

13 g 5 g

Mass of product = 13 g + 5 g = 18 g

The product contains 5 g of nitrogen .

$\text{Percent N} = \dfrac{\text{5 g}}{\text{18 g}} \times \, 100\% = \mathbf{28 \, \%}\\\text{The percent by mass of nitrogen is $\large \boxed{\mathbf{28 \, \% }}$}$

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3 years ago

A sample of SO2 gas occupies 45.6 L at 373 K and 3.45 atm. This sample contains how many moles of oxygen atoms?

lisov135 [29]

Answer:

10.28 mol

Explanation:

S + 2O = SO2

(atm x L) ÷ (0.0821 x K)

(3.45 x 45.6) ÷ (0.0821 x 373)

=5.13726

Then round it to significant figures

=5.14

5.14 mol SO2 x (2 mol O ÷ 1 mol SO2)

=10.28 mol O

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3 years ago

How many particles would be found in a 1.224 g sample of K2O

lbvjy [14]

Answer:

9.96*10^21

Explanation:

Molar mass of K2O=29*2+16

= 74g per mol

number of moles in the sample= 1.224/ 74

=0.1654

Number of particles in 1 mole=6.0221409*10^23

Number of particles= 0.01654*6.0221409*10^23

=9.96*10^21

4 0

3 years ago

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