Mass in kilograms of liquid air required = 0.78 kg
<u>Given that </u>
1 Litre of liquid air contains 1.3 grams of oxygen ( air )
<u />
<u> Determine the a</u><u>mount of liquid air</u><u> in Kg</u>
volume of air given = 600 L
mass of liquid air required = x
1 litre = 1.3 grams
600 L = x
∴ x ( mass of liquid air ) = 1.3 * 600
= 780 g = 0.78 kg
Hence we can conclude that Mass in kilograms of liquid air required = 0.78 kg
Learn more about liquid air : brainly.com/question/636295
If you add salt to water then it will boil faster than water without salt
An example of a reaction that occurs within the core of a nuclear reactor is the nuclear fission reaction given:
- ²³⁵₉₂U + ¹₀n ---> ⁹⁰₃₈Sr + ¹⁴³₅₄ + 3 ¹₀n
<h3>What is a nuclear reactor?</h3>
A nuclear reactor is a device which produces electrical energy as a result of the nuclear reactions that take place within it.
In a nuclear reactor, the reaction that takes place within the core is a nuclear fission chain reaction.
In a nuclear fission reaction, the nucleus of larger atoms are split into the nucleus of smaller atoms when fast moving neutrons are used to bombard the nucleus of the large atom. The fission of the nucleus of the large atom results in the formation of atoms of lighter nucleus as well as more protons which then bombard more nucleus of the large atoms resulting in a chain reaction.
The chain reaction occurring within the nuclear reactor core is controlled by the insertion of boron rods which absorbs the excess neutrons produced.
An example of a reaction that occurs within the core of a nuclear reactor is given below:
²³⁵₉₂U + ¹₀n ---> ⁹⁰₃₈Sr + ¹⁴³₅₄ + 3 ¹₀n
Learn more about nuclear fission at: brainly.com/question/913303
#SPJ1
Volume of a substance can be determined by dividing mass of the substance by its density.
That can be mathematical shown as:
Density=Mass/Volume
So, Volume=Mass/Density
Here mass of the substance given as 24.60 g
Whereas density of the substance is 2.70 g/mL
So,
Volume=Mass/Density
=24.6/2.7
=9.1 mL
So volume of the substance is 9.1 mL.
Jdjdjxjjznbxyhzkaishsbzn
Kzksjdjjdidiididjdjdjj
Sksk