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Olegator [25]
4 years ago
11

AlCl3 + Na NaCl + Al Did Cl change oxidation number?

Chemistry
2 answers:
gizmo_the_mogwai [7]4 years ago
6 0
Yes. If this is the balanced equation:

AlCl3 + 3Na —— 3NaCl + Al

then Al was reduced from a 3+ oxidation (to neutralize the 3- from the chlorine) to a 0 oxidation (elemental ground state).
damaskus [11]4 years ago
5 0

Answer : There is no change takes place in the oxidation number of Cl.

Explanation :

The given chemical reaction is,

AlCl_3+Na\rightarrow NaCl+Al

This reaction is an unbalanced reaction because the chlorine atoms are not balanced.

In order to balance the chemical reaction, the coefficient 3 is put before the Na and NaCl.

The balanced chemical reaction will be,

AlCl_3+3Na\rightarrow 3NaCl+Al

Now we have to calculate the oxidation number of all the elements.

In AlCl_3, the oxidation number of Al and Cl are, (+3) and (-1) respectively.

The oxidation number Na and Al are, zero (0)

In NaCl, the oxidation number of Na and Cl are, (+1) and (-1) respectively.

From this we conclude that the oxidation number of Cl changes from (-1) to (-1) that means remains same.

Therefore, there is no change takes place in the oxidation number of Cl.

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Harrizon [31]

Answer:

27.60 g urea

Explanation:

The <em>freezing-point depression</em> is expressed by the formula:

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In this case,

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m is the molality of the urea solution in X (mol urea/kg of X)

First we<u> calculate the molality</u>:

  • 6.5 °C = 7.78 °C kg·mol⁻¹ * m
  • m = 0.84 m

Now we<u> calculate the moles of ure</u>a that were dissolved:

550 g X ⇒ 550 / 1000 = 0.550 kg X

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Finally we <u>calculate the mass of urea</u>, using its molecular weight:

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7 0
3 years ago
Compare and Contrast the differences between plant animal cells.
sergij07 [2.7K]

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8 0
3 years ago
A chemical engineer must calculate the maximum safe operating temperature of a high-pressure gas reaction vessel. The vessel is
Airida [17]

Answer:

the maximum safe operating temperature the engineer should recommend for this reaction is 616 °C  

Explanation:

Given the data in the question;

First we calculate the Volume of the steel cylinder;

V = πr²h

radius r = Diameter / 2 = 27 cm / 2 = 13.5 cm

height h = 32.4 cm

so we substitute

V = π × ( 13.5 cm )² × 32.4 cm

V  = π × 182.25 cm × 32.4 cm

V = 18550.79 cm³  

V = 18.551 L

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vessel contains 0.218kg or 218 gram of carbon monoxide gas

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we know that;

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T = PV / nR

we know that gas constant R = 0.0820574 L•atm•mol⁻¹ K⁻¹

so we substitute

T = ( 30.5946 × 18.551 ) / ( 7.7829 × 0.082 )

T = 567.5604 / 0.6381978

T = 889.317387 K

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6 0
3 years ago
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max2010maxim [7]

Answer:

A. The rate of heat transfer through the material would increase.

Explanation:

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So if we increase the rate of flow of cooling water and the other variables that ypu can control remain the same, the result is that the rate of heat transfer through the material would increase, as it is stated in option a.

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Answer:

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