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natulia [17]
4 years ago
11

A ring is attached at the center of the underside of a trampoline. A sneaky teenager crawls under the trampoline and uses the ri

ng to pull the trampoline slowly down while his 67-kg mother is sleeping on it. When he releases the trampoline, she is launched upward. As she passes through the position at which she was before her son stretched the trampoline, her speed is 3.0m/s.
How much elastic potential energy did the son add to the trampoline by pulling it down? Assume the interaction is nondissipative.
Physics
1 answer:
IRINA_888 [86]4 years ago
6 0

Answer:

E = 301.5 J

Explanation:

We have,

Mass of mother, m = 67 kg

Here, a sneaky teenager crawls under the trampoline and uses the ring to pull the trampoline slowly down. As she passes through the position at which she was before her son stretched the trampoline, her speed is 3 m/s.

It is required to find the elastic potential energy the son add to the trampoline by pulling it down. It is based on the conservation of energy.

The elastic potential energy of the mother = the elastic potential energy the son add to the trampoline.

\dfrac{1}{2}mv^2=\dfrac{1}{2}kx^2

So, the elastic potential energy is :

E=\dfrac{1}{2}mv^2\\\\E=\dfrac{1}{2}\times 67\times 3^2\\\\E=301.5\ J

So, the elastic potential energy of 301.5 J the son add to the trampoline by pulling it down.

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3 years ago
These little bunnies (A, B, and C) were born in the same litter to the same parents, but they have different traits for the feat
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Answer/Explanation:

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Say the mother has one version of the gene that gives thick ears (A), and one version of the gene that gives thin ears (a). So she is Aa.

Say the father has the same, and he is also Aa.

The father can pass on either A or a, and the mother can pass on either A or a.

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Answer:

Explanation:

Newton's law states that F=mg, or in other applications F=ma, where:

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In your question we know the following variables:

The mass of the arrow (m= 100g, however we should use kilograms- 0.1kg)

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hope this helps :)

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