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Ghella [55]
3 years ago
6

A horizontal wire supports it weight in a 0.001T magnetic field, oriented orthogonally to the wire. This is due to current runni

ng from left to right in the wire. Calculate the current through this wire that will just support the weight of the wire (over the length of the wire). The length of the wire is 0.5 m, and the mass of the 0.5 m section is 50 g. [give your answer in units of Amps]
Physics
1 answer:
Ierofanga [76]3 years ago
4 0

Answer:

Explanation:

Force on a current carrying wire in a magnetic field

= B i L where B is magnetic field , i is current and L is length of the wire .

Putting in the given values in the question

force on a current carrying wire in a magnetic field  = .001 T x i x .5 m

5 x 10⁻⁴ i  N .

weight of the wire = .050 kg x 9.8 m/s²

= .49 N .

For equilibrium

5 x 10⁻⁴ i  = .49

i = 980 A .

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2. A 56N force is exerted on an 8kg object. What is the object's acceleration?
White raven [17]

acceleration = 7 m/s²

Explanation:

To determine the object's acceleration we use the following formula:

force (N) = mass (kg) × acceleration (m/s²)

acceleration (m/s²) = force (N) / mass (kg)

acceleration = 56 N / 8 kg

acceleration = 7 m/s²

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7 0
3 years ago
Saatlemati
vodomira [7]

Answer:

what are u asking there isnt a question

3 0
3 years ago
a wrench weighs 5.24 newtons on earth. when it is taken to the Moon, where g =1.16 m/s2 how much does it weigh?
Andrew [12]

“Weight of the wrench” on “the moon” is “6.07 kg”.

<u>Explanation</u>:

Weight of the wrench is 5.24 N  

Weight of the wrench in kilograms = W × g

Taken “g” on the moon is 1.16 \mathrm{m} / \mathrm{s}^{2}

=5.24 \mathrm{N} \times 9.81 \mathrm{m} / \mathrm{s}^{2}=51.352 \mathrm{kg}

Weight of the wrench in kilograms is 51.352 kg.

Formula to calculate weight of the object on the moon is

\frac{\text {weight of the object on earth}}{9.81 \mathrm{m} / \mathrm{s}^{2}} \times 1.16 \mathrm{m} / \mathrm{s}^{2}

Substitute the values given,

=\frac{51.352 \mathrm{kg}}{9.81 \mathrm{m} / \mathrm{s}^{2}} \times 1.16 \mathrm{m} / \mathrm{s}^{2}

=5.234 \times 1.16

= 6.07 kg

Therefore, weight of the wrench on the moon is 6.07 kg.  

6 0
3 years ago
A bus initially moving at 20 m/s with an acceleration of -4m/s² for 5
Alborosie

Answer:

50m; 0m/s.

Explanation:

Given the following data;

Initial velocity = 20m/s

Acceleration, a = - 4m/s²

Time, t = 5secs

To find the displacement, we would use the second equation of motion;

S = ut + \frac {1}{2}at^{2}

Substituting into the equation, we have;

S =20*5 + \frac{1}{2}*(-4)*5^{2}

S =100 + (-2)*25

S =100 - 50

S = 50m

Next, to find the final velocity, we would use the third equation of motion;

V^{2} = U^{2} + 2aS

Where;

  • V represents the final velocity measured in meter per seconds.
  • U represents the initial velocity measured in meter per seconds.
  • a represents acceleration measured in meters per seconds square.

<em>Substituting into the equation, we have;</em>

V^{2} = 20^{2} + 2(-4)*50

V^{2} = 400 - 400

V^{2} = 0

V = 0m/s

<em>Therefore, the displacement of the bus is 50m and its final velocity is 0m/s.</em>

5 0
3 years ago
The drawing shows two thermometers, A, and B, whose temperatures are measured in °A and °B. The ice and boiling points of water
Rama09 [41]
Unf there's no diagram. but this looks like a sort of celsius to fahrenheit temp scale conversion sort of problem.
6 0
3 years ago
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