Answer:
The sport utility vehicle was traveling at V2= 11.5 m/s.
Explanation:
m1= 1090 kg
V1= 30.4 m/s
m2= 2880 kg
V2= ?
m1*V1 = m2*V2
V2= (m1*V1)/m2
V2= 11.5 m/s
Answer:
Force is classified as a push or a pull
Explanation:
The velocity at the maximum height will always be 0. Therefore, you will count your final velocity as 0, and your initial velocity as 35 m/s. Next, we know that the acceleration will be 9.8 m/s^2. How? Because the ball is thrown directly upward, and the only force acting on it will be the force of gravity pushing it back down.
The formula we use is h = (Vf^2 - Vi^2) / (2*-9.8m/s^2)
Plugging everything in, we have h = (0-1225)/(19.6) = 62.5 meters is the maximum height.
