All categories

3 years ago

The equation K2O represents the ionic bond between potassium and oxygen. What is the name of the compound?

Chemistry

2 answers:

eduard3 years ago

5 0

Ten name if this compound is Potassium Oxide

andriy [413]3 years ago

5 0

Answer: potassium oxide.

Explanation:

$K_2O$ is an ionic compound because potassium element is a metal and oxygen element is a non-metal. The bond formed between a metal and a non-metal is always ionic in nature.

The nomenclature of ionic compounds is given by:

1. Positive is written first.

2. The negative ion is written next and a suffix is added at the end of the negative ion. The suffix written is '-ide'.

Hence, the name of $K_2O$ is potassium oxide.

You might be interested in

Why is it important to know what temperature scale is being used in a given situation?

Arisa [49]

It depends, for example, it is quite important to know the Kelvin scale (i.e 0 degrees Celsius is 273 K and -273 degrees Celsius is 0 K ) when dealing gases. But I don't know other situations where you would need to know other temperature scales.

Hope this helps and also if you are using Fahrenheit 1 Fahrenheit is -17.22 degrees Celsius

4 0

3 years ago

Need help setting the problem up

Sveta_85 [38]

Answer:

4.0 moles

Explanation:

The following data were obtained from the question:

Volume (V) = 12L

Pressure = 5.6 atm

Temperature (T) = 205K

Gas constant (R) = 0.08206 atm.L/Kmol

Number of mole (n) =?

Using the ideal gas equation: PV = nRT, the number of mole of the gas can be obtained as follow

PV = nRT

5.6 x 12 = n x 0.08206 x 205

Divide both side by 0.08206 x 205

n = (5.6 x 12)/(0.08206 x 205)

n = 4.0 moles

Therefore, the number of mole of the gas is 4.0 moles

5 0

3 years ago

How many moles of calcium, Ca, are in 5.00 g of calcium?

Rom4ik [11]

<h3>Answer:</h3>

0.125 mol Ca

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

<u>Chemistry</u>

<u>Atomic Structure</u>

Reading a Periodic Table
Using Dimensional Analysis

<h3>Explanation:</h3>

<u>Step 1: Define</u>

5.00 g Ca

<u>Step 2: Identify Conversions</u>

Molar mass of Ca - 40.08 g/mol

<u>Step 3: Convert</u>

Set up: $\displaystyle 5.00 \ g \ Ca(\frac{1 \ mol \ Ca}{40.08 \ g \ Ca})$
Multiply: $\displaystyle 0.12475 \ mol \ Ca$

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 3 sig figs.</em>

0.12475 mol Ca ≈ 0.125 mol Ca

3 0

2 years ago

Please show all work:

Tom [10]

If 40.0 grams of magnesium is reacted with an excess of nitric acid. 3.3 g of hydrogen gas will be produced.

<h3>What is Stoichiometry ?</h3>

Stoichiometry helps us use the balanced chemical equation to measure quantitative relationships and it is to calculate the amounts of products and reactants that are given in a reaction.

<h3>What is Balanced Chemical Equation ?</h3>

The balanced chemical equation is the equation in which the number of atoms on the reactant side is equal to the number of atoms on the product side in an equation.

Now we have to write the balanced equation

Mg + 2HNO₃ → Mg(NO₃)₂ + H₂

According to Stoichiometry

$40.9\ \text{g Mg} \times \frac{1\ \text{mol Mg}}{24.31\ \text{g Mg}} \times \frac{1\ \text{mol}\ H_2}{1\ \text{mol Mg}} \times \frac{2.02\ g\ H_2}{1\ \text{mol}\ H_2}$

= 3.3 g H₂

Thus from the above conclusion we can say that If 40.0 grams of magnesium is reacted with an excess of nitric acid. 3.3 g of hydrogen gas will be produced.

Learn more about the Stoichiometry here: brainly.com/question/16060223

#SPJ1

8 0

2 years ago

If 20.0 ml of glacial acetic acid (pure hc2h3o2) is diluted to 1.40 l with water, what is the ph of the resulting solution? the

Y_Kistochka [10]

By using the formula, mass = density x volume, we calculate mass in grams

20.0 mL CH₃COOH x (1.05 g / mL) = 21.0 g CH₃COOH

To find the moles, molar mass of CH₃COOH = 60.05g/mol<span>

21.0 g </span>CH₃COOH x (1 mole CH₃COOH / 60.05 g CH₃COOH) = 0.350 moles CH₃COOH

To find molarity,<span>

[</span>CH₃COOH] = moles CH₃COOH / L of solution = 0.350 / 1.40 = 0.250 M CH₃COOH<span>

When </span>CH₃COOH is dissolved in water, it produces small and equal amounts of H₃O⁺+ and C₂H₃O₂⁻.

<span>
Molarity , </span>CH₃COOH<span> + H</span>₂O <==> H₃O⁺ + C₂H₃O₂⁻

<span> <span>Initial 0.250 0 0 </span>
Change -x x x
Equilibrium 0.250-x x x

K</span>ₐ = [H₃O⁺][C₂H₃O₂⁻] / [HC₂H₃O₂] = (x)(x) / (0.250-x) = 1.8 x 10⁻⁵

<span>Since K</span>ₐ is relatively small, we can neglect the -x term after 0.250 to simplify

<span>x</span>² / 0.250 = 1.8 x 10⁻⁵

x² = 4.5 x 10⁻⁶

<span> x = 2.1 x 10</span>⁻³<span> = [H</span>₃O⁺]

pH = -log [H₃O⁺] = -log (2.1 x 10⁻³) = 2.68

8 0

3 years ago