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2 years ago

The equation K2O represents the ionic bond between potassium and oxygen. What is the name of the compound?

Chemistry

2 answers:

eduard2 years ago

5 0

Ten name if this compound is Potassium Oxide

andriy [413]2 years ago

5 0

Answer: potassium oxide.

Explanation:

$K_2O$ is an ionic compound because potassium element is a metal and oxygen element is a non-metal. The bond formed between a metal and a non-metal is always ionic in nature.

The nomenclature of ionic compounds is given by:

1. Positive is written first.

2. The negative ion is written next and a suffix is added at the end of the negative ion. The suffix written is '-ide'.

Hence, the name of $K_2O$ is potassium oxide.

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Give the reason for the following; 1. Iodimetric titrations are usually performed in neutral or mildly alkaline (pH 8) to weakly

Agata [3.3K]

Answer:

Explanation:

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2 years ago

Given: 4Na + O2 → 2Na2O In this chemical reaction, how many moles of Na2O will be produced if 2.90 moles of Na react completely?

crimeas [40]

Since we already have the balanced equation, we know that the ratio between $Na:Na_{2}O$ is $4:2$ respectively.

So then we can set up a proportion to find the number of moles produced when 2.90 moles of Na react completely:

$\frac{4mol_{Na}}{2mol_{Na_{2}O}} =\frac{2.90mol_{Na}}{xmol_{Na_{2}O}}$

Then we cross multiply and solve for x:

$4x=5.8$

$x=1.45$

Therefore, we know that when 2.90 moles of Na react completely, there are 1.45 moles of $Na_{2}O$ that are produced.

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2 years ago

Zachary adds 9.7 g to 1.114 g.<br> How many significant figures should his answer have?

makvit [3.9K]

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2 years ago

Nuclear power plants use uranium, a nonrenwable resource, for fuel

Crazy boy [7]

True. Although nuclear energy itself is renewable, the material (uranium) used in nuclear power plants is not.

7 0

2 years ago

If 4.65 LL of CO2CO2 gas at 22 ∘C∘C at 793 mmHg mmHg is used, what is the final volume, in liters, of the gas at 35 ∘C∘C and a p

otez555 [7]

Answer:

About 7.9 L.

Explanation:

We can utilize the ideal gas law. Recall that:

$\displaystyle PV = nRT$

Because the amount of carbon dioxide does not change, we can rearrange to formula to:
$\displaystyle \frac{PV}{T}= nR$

Because the right-hand side stays constant, we have that:
$\displaystyle \frac{P_1V_1}{T_1} = \frac{P_2V_2}{T_2} = nR$

Hence substitute initial values and known final values:
$\displaystyle \begin{aligned} \frac{(793\text{ mm Hg})(4.65 \text{ L})}{(22 \text{ $^\circ$C})} & = \frac{(743 \text{ mm Hg})V_2}{(35\text{ $^\circ$C})} \\ \\ V_2 & = 7.9\text{ L}\end{aligned}$

Therefore, the final volume is about 7.9 L.

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2 years ago