Since the ladder is standing, we know that the coefficient
of friction is at least something. This [gotta be at least this] friction
coefficient can be calculated. As the man begins to climb the ladder, the
friction can even be less than the free-standing friction coefficient. However,
as the man climbs the ladder, more and more friction is required. Since he
eventually slips, we know that friction is less than what's required at the top
of the ladder.
The only "answer" to this problem is putting lower
and upper bounds on the coefficient. For the lower one, find how much friction
the ladder needs to stand by itself. For the most that friction could be, find
what friction is when the man reaches the top of the ladder.
Ff = uN1
Fx = 0 = Ff + N2
Fy = 0 = N1 – 400 – 864
N1 = 1264 N
Torque balance
T = 0 = N2(12)sin(60) – 400(6)cos(60) – 864(7.8)cos(60)
N2 = 439 N
Ff = 439= u N1
U = 440 / 1264 = 0.3481
Answer: im trying to find the same answer too
Explanation
The formula to find the radius is R=V^2/A or Radius=Velocity^2/Acceleration so that means
R=V^2/A
10^2/5=R
100/5=R
R=20m
Answer:
Leading among the causes of unsustainable agriculture are inadequate or inappropriate policies which include pricing, subsidy and tax policies which have encouraged the excessive, and often uneconomic, use of inputs such as fertilizers and pesticides, and the overexploitation of land.
Explanation:
