7. Slope of AD = 4/16 = 1/4
8. ΔAEC = 3/12 = 1/4
.. ΔDFB = 2/8 = 1/4
9. The angles at E, G, and F are right angles. Lines CE and BF are parallel, so the alternate interior angles at B and C where the transversal AD crosses them are equal. The triangles of interest are similar by AA~.
10. See problem 7. The ratio is the same.
11. Hard to tell what rule they want you to state. Every axis-aligned right triangle with its hypotenuse on AD will have the same ratio of side lengths. (That's one of the features of the graph of a line. It has the same slope everywhere, measured over any distance.)
Answer:
The correct options are a and b.
Step-by-step explanation:
It is given that triangle ABC with segment AD drawn from vertex A and intersecting side BC.
Two triangle are called similar triangle if their corresponding sides are proportional or the corresponding interior angle are same.
To prove ΔABC and ΔDBA are similar, we have to prove that corresponding interior angles of both triangle as same.
If segment AD is an altitude of ΔABC, then angle ADB is a right angle.

The opposite angle of hypotenuse is right angle. If segment CB is a hypotenuse, then angle ABC is a right angle.

In triangle ΔABC and ΔDBA
(Reflexive property)
(Right angles)
By AA rule of similarity ΔABC and ΔDBA are similar.
Therefore correct options are a and b.
Answer:
1.1%
Step-by-step explanation:
22- 17 = 5% of 22 = 1.1