The answer is A. As the first statement is a true statement. Hope this help you
Answer:

Explanation:
<u>1. Calculate the mass of C in 1.24 g of CO₂</u>

<u>2. Calculate the mass of H in 0.255g of H₂O</u>

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<u>3. Calculate the mass of O by difference</u>

<u>4. Convert every mass to number of moles:</u>
- C: 0.3384g / (12.011g/mol) = 0.02817 mol
- H: 0.02854g / (1.008g/mol) = 0.02831 mol
- O: 0.15206g / (15.999g/mol) = 0.009504 mol
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<u>5. Divide every number of moles by the least number of moles (0.009504):</u>
- C: 0.02817/0.009504 = 2.96 ≈ 3
- H: 0.02831 / 0.009504 ≈ 3
- O: 0.009504 / 0.009504 = 1
<u>6. Those numbers are the respective subscripts in the empirical formula:</u>

The formula of the hydrate = CuSO₄• 3H₂O
<h3>Further explanation</h3>
Given
4.175 grams sample CuSO₄• xH₂O
3.120 grams anhydrous compound CuSO₄
Required
The formula
Solution
mass of H₂O driven off :
= 4.175 - 3.12
= 1.055 g
MW CuSO₄ = 159.5 g/mol
MW H₂O = 18 g/mol
mol ratio of CuSO₄ : H₂O :
= 3.12/159.5 : 1.055/18
= 0.01956 : 0.05861
= 1 : 3
Answer:
your answer is b. chlorofluorocarbon(CFC
Explanation:
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The answer is in the picture which is given below: