Answer:
Electronic Configuration of calcium ion: Ca²⁺
1s², 2s², 2p⁶, 3s², 3p⁶
Explanation:
Calcium belong to group IIA and known as alkaline earth metals.
- it have two electrons in outer most orbital.
- these outer two electrons are involve in bonding
- calcium lose these two electron and form cation
- cation have 2+ charge
- calcium have total twenty electrons
Electronic Configuration of calcium atom: ²⁰Ca
1s², 2s², 2p⁶, 3s², 3p⁶, 4s²
When calcium ion is form it loses two electron and have 2+ charge on it.
and have total of 18 electrons
So,
Electronic Configuration of calcium ion: Ca²⁺
the last filled orbital will be 3p⁶
1s², 2s², 2p⁶, 3s², 3p⁶
Answer:
81.97 g of NaAl(OH)₄
Solution:
The reaction for the preparation of Sodium Aluminate from Aluminium Metal and NaOH is as follow,
2 NaOH + 2 Al + 6 H₂O → 2 NaAl(OH)₄ + 3 H₂
According to this equation,
2 Moles of NaOH produces = 163.94 g (2 mole) of NaAl(OH)₄
So,
1 Mole of NaOH will produce = X g of NaAl(OH)₄
Solving for X,
X = (1 mol × 163.94 g) ÷ 2 mol
X = 81.97 g of NaAl(OH)₄
Alcohols always contain the Hydroxyl functional group (-O H) - (or just hydroxyl group), which is an oxygen atom bound by a covalent (with shared electron pairs) bound to a hydrogen atom.
Answer:
The answers are options b , c and d.
Hope this helps.