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timurjin [86]
3 years ago
15

The addition of 9.0×105 J is required to convert a block of ice at -10 ∘C to water at 11 ∘C. i need help this is due in less tha

n 15 minutes​
Physics
1 answer:
Law Incorporation [45]3 years ago
8 0

The mass of the block of ice is 2.24 kg

Explanation:

The amount of heat needed for the whole process consists of three different amounts of heat:

Q_1: the amount of heat needed to raise the temperature of the block of ice from -10^{\circ}C to 0^{\circ}C

Q_2: the amount of heat needed to melt the block of ice at melting point

Q_3: the amount of heat needed to raise the temperature of the water from 0^{\circ}C to 11^{\circ}C

The total amount of heat needed can be written as

Q=Q_1+Q_2+Q_3=mC_i\Delta T_1 + m\lambda_f + mC_w\Delta T_3

where we have:

Q=9.0 \cdot 10^5 J (total amount of heat required)

m is the mass of the block of ice

C_i = 2108 J/kg^{\circ}C is the specific heat of ice

\lambda_f=3.34\cdot 10^5 J/kg is the latent heat of fusion of ice

C_w=4186 J/kg^{\circ}C is the specific heat capacity of water

\Delta T_1 = 0-(-10)=10^{\circ}C is the change in temperature in the 1st process

\Delta T_3 = 11-0=11^{\circ}C is the change in temperature in the 3rd process

Solving the equation for m, we find the mass of the block of ice:

m=\frac{Q}{C_i\Delta T_1 + \lambda_f+C_w\Delta T_3}=\frac{9.0\cdot 10^5}{(2108)(10)+3.34\cdot 10^5+(4186)(11)}=2.24 kg

Learn more about specific heat capacity:

brainly.com/question/3032746

brainly.com/question/4759369

#LearnwithBrainly

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