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3 years ago

Please answer correctly cause I am not really sure..

2 answers:

7 0

The full cycle of moon phases averages 29.531 days. A quarter of that is 7.38 days. So "7 days" is a pretty good approximation for casual conversation. It's true.

valkas [14]3 years ago

5 0

Answer:True

Explanation:

The full cycle of the moon is 29.631 or we could say 29.5 and the quarter is 7.34 I think so yes it’s true it’s appropriately a full average and if you subtract this two it true

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An airplane is accelerating forward due to a force of 3320 newtons acting 30 on it. Then it encounters wind resistance that exer

Soloha48 [4]

For the purpose of the problem we can consider only the motion on the x-axis (horizontal direction).
We have two forces:the horizontal component of the force F of 3320 N acting forward, and the backward force of 550 N.
The horizontal component of the forward force is
$3320 N \cdot cos 30^{\circ} = 2875 N$
So, the net force is
$F_{net} = 2875 N - 550 N =2325 N$
in the forward direction.

4 0

3 years ago

What is x-rays ? and how it's formed ?

tia_tia [17]

X - rays are highly penetrating electromagnetic radiations that are formed when the cathode rays strikes a dense metal.

It has many characteristics such as :

bears no charge.

travels with the speed of light.

can ionize gases.

3 0

3 years ago

Marvin uses a long copper wire with resistivity 1.68 x 10^-8 Ω⋅m and diameter 1.00 x 10^−3 m to create a solenoid that has a 3

Mazyrski [523]

Answer with Explanation:

We are given that

Resistivity of copper wire= $\rh0=1.68\times 10^{-8}\Omega m$

Diameter=d= $1.00\times 10^{-3} m$

Radius of copper wire= $r=\frac{d}{2}=\frac{1}{2}\times 10^{-3} m$

Radius of solenoid=r' $=3 cm=3\times 10^{-2} m$

1 m=100 cm

a.Length of wire=l=11.3 m

Area of wire=A= $\pi r^2$

Where $\pi=3.14$

A= $3.14\times (\frac{1}{2}\times 10^{-3})^2$

Resistance, R= $\rho \frac{l}{A}$

Using the formula

$R=1.68\times 10^{-8}\times\frac{11.3}{3.14\times (\frac{1}{2}\times 10^{-3})^2}$

$R=0.24\Omega$

B.Length of solenoid= $2\pi r'=2\times 3.14\times 3\times 10^{-2}=0.188$ m

Number of turns= $n_0=\frac{l}{2\pi r'}=\frac{11.3}{0.188}$

$n_0$ =60

C.Potential difference,V=3 V

Current,I= $\frac{V}{R}$

I= $\frac{3}{0.24}=12.5 A$

D.Total length =0.1 m

Number of turns per unit length,n= $\frac{60}{0.1}=600$

Magnetic field along central axis inside of the solenoid,B= $\mu_0 nI$

$B=4\pi\times 10^{-7}\times 12.5\times 600=9.42\times 10^{-3} T$

4 0

3 years ago

Read 2 more answers

What is the magnitude of an electric field in which the electric force on a proton is equal in magnitude to its weight?Use 1.67×

vazorg [7]

The electric force on the proton is:

F = Eq

F = electric force, E = electric field strength, q = proton charge

The gravitational force on the proton is:

F = mg

F = gravitational force, m = proton mass, g = gravitational acceleration

Since the electric force and gravitational force balance each other out, set their magnitudes equal to each other:

Eq = mg

Given values:

q = 1.60×10⁻¹⁹C, m = 1.67×10⁻²⁷kg, g = 9.81m/s²

Plug in and solve for E:

E(1.60×10⁻¹⁹) = 1.67×10⁻²⁷(9.81)

E = 1.02×10⁻⁷N/C

5 0

3 years ago

Sobre un barco, que se mueve en forma rectilínea, y con velocidad constante de 30 [km/h], se mueve un perro en el mismo sentido

almond37 [142]

Answer:

El observador verá correr al perro sobre la cubierta del barco a una velocidad de 40 kilómetros por hora.

Explanation:

Para determinar la velocidad del perro con respecto al observador sentado desde la playa a través del concepto de velocidad relativa, descrito en la siguiente fórmula:

$v_{P/B} = v_{P} - v_{B}$ (1)

Donde:

$v_{P/B}$ - Velocidad del perro relativo al barco, en kilómetros por hora.

$v_{P}$ - Velocidad del perro con respecto al observador, en kilómetros por hora.

$v_{B}$ - Velocidad del barco con respecto al observador, en kilómetros por hora.

Si sabemos que $v_{B} = 30\,\frac{km}{h}$ y $v_{P/B} = 10\,\frac{km}{h}$ , entonces la velocidad del perro con respecto al observador es:

$v_{P} = v_{B} + v_{P/B}$

$v_{P} = 30\,\frac{km}{h} + 10\,\frac{km}{h}$

$v_{P} = 40\,\frac{km}{h}$

El observador verá correr al perro sobre la cubierta del barco a una velocidad de 40 kilómetros por hora.

6 0

3 years ago