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Ber [7]
2 years ago
12

Epidemiological studies looks into:

Chemistry
1 answer:
Yanka [14]2 years ago
8 0

Answer:

It is used in medical research.

Explanation:

So its answer is trends in drug effectiveness

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natta225 [31]
The Moon completes one orbit around the Earth in approximately 27 1/3 days and completes one cycle of its phases in approximately 29 1/2 days. The correct option among all the options that are given in the question is the second option. I hope that this is the answer that has come to your great help.
4 0
3 years ago
I need information about <br>"forming colloid"<br>THANK YOU! ​
notka56 [123]

Answer:

Condensation methods from colloidal particles by aggregation of molecules or ions. Examples of colloids are really in common in evryday life, eg. Mayonnaise, butter, milk, gelatin, paper etc..

Every colloid consists of two parts :colloidal particles and the dispersing medium.

3 0
3 years ago
Given that a theoretical yield for isolating Calcium Carbonate in this experiment would be 100%. From that information and based
Stels [109]

Answer:

It's well Explained below.

Explanation:

First of Excess product of CaCO_3 would be produced due to the fact that there would not be enough CaCl_2 to react with Na_2•CO_3. The main purpose of having stoichiometric quantities is for us to know the correct amount or near the correct amount of each reactant in order to create a product that will be close to the theoretical amount and thus have a higher percent yield.

8 0
3 years ago
Given a solution with a pOH of 13.6, what is the [OH-] of the solution?
Lelechka [254]
10^-13.6 = 2.51x10^-14
8 0
3 years ago
Read 2 more answers
Neptunium-237 undergoes a series of α-particle and β-particle productions to end up as thallium-205. How many α particles and β
Fantom [35]
<h3>Answer:</h3>

8 alpha particles

4 beta particles

<h3>Explanation:</h3>

<u>We are given;</u>

  • Neptunium-237
  • Thallium-205
  • Neptunium-237 undergoes beta and alpha decay to form Thallium-205.

We are required to determine the number of beta and alpha particles produced to complete the decay series.

  • We need to know that when a radioisotope emits an alpha particle the mass number reduces by 4 while the atomic number decreases by 2.
  • When a beta particle is emitted the mass number of the radioisotope increases by 1 while the atomic number remains the same.

In this case;

Neptunium-237 has an atomic number 93, while,

Thallium-205 has an atomic number 81.

Therefore;

²³⁷₉₃Np → x⁴₂He + y⁰₋₁e + ²⁰⁵₈₁Ti

We can get x and y

237 = 4x + y(0) + 205

237-205 = 4x

4x = 32

 x = 8

On the other hand;

93 = 2x + (-y) + 81

but x = 8

93 = 16 -y + 81

y = 4

Therefore, the complete decay equation is;

²³⁷₉₃Np → 8⁴₂He + 4⁰₋₁e + ²⁰⁵₈₁Ti

Thus, Neptunium-237 emits 8 alpha particles and 4 beta particles to become Thallium-205.

5 0
3 years ago
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