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larisa86 [58]
4 years ago
5

Determine how many atoms of pure silver will be created when 19.83 x 1023 atoms of copper are used in the following reaction:

Chemistry
1 answer:
nadezda [96]4 years ago
8 0

Answer : The number of silver atoms produced will be 39.66\times 10^{23}

Explanation : Given,

Number of atoms of copper = 19.83\times 10^{23}

The given balanced chemical reaction,

Cu+2AgNO_3\rightarrow Cu(NO_3)_2+2Ag

From the balanced chemical reaction we conclude that,

As, 6.02\times 10^{23} number of copper atoms react to give 2\times 6.02\times 10^{23} number of silver atoms.

So, 19.83\times 10^{23} number of copper atoms react to give 2\times \frac{6.02\times 10^{23}}{6.02\times 10^{23}}\times 19.83\times 10^{23}=39.66\times 10^{23} number of silver atoms.

Therefore, the number of silver atoms produced will be 39.66\times 10^{23}

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