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koban [17]
2 years ago
14

When sound waves interfere to create standing waves, the points on the medium that move up and down with the largest amplitudes

are called __________?
Physics
2 answers:
malfutka [58]2 years ago
7 0
The correct answer is: Anti-nodes.

Explanation:

When the interference between the two waves is constructive and the <span>points on the wave that undergo the maximum displacement during each vibrational cycle </span><span>of the standing wave </span>back and forth. Those points are called anti-nodes. Hence, in the case of sound waves, interference creates standing waves, and the points on the medium that move up and down with the highest amplitudes are called anti-nodes.

irina [24]2 years ago
6 0
Answer: antinodes.

A standing wave is created when two waves in a medium interfere in such a way that certain points along the medium appear to stand still.

Indeed, the points at which the interference between the two waves is completely destructive show no displacement. These points are called <em>nodes</em>.

There are also points at which the interference between the two waves is completely constructive and these points appear to vibrate from a large positive position to a large negative position and back. These points are called antinodes.
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Answer:

39.240 W

Explanation:

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4 0
2 years ago
Read 2 more answers
Tres litros de oxigeno gaseoso a 15 grados centígrados y a presión atmosférica (1atm), se lleva a una presión de 10mm de Hg. ¿ c
lana [24]

Answer:

Three liters of gaseous oxygen at 15 degrees Celsius and at atmospheric pressure (1atm), is brought to a pressure of 10mm Hg. What will be the volume of the gas now if the temperature has not changed?

Explanation:

Given that, the temperature is constant

Then, using gay Lussac law

P1•V1 / T1 = P2•V2 / T2

Since temperature is constant

Then, T1 = T2 = T and they cancels out

So, we are left with

P1•V1 = P2•V2

Given that, .

Initial volume

V1 = 3 litres.

Initial pressure

P1 = 1atm = 101325 Pa

Final pressure

P2 = 10mmHg = 1333.22 Pa

Then, we want to find the final volume V2

Make V2 subject of formula.

V2 = V1•P1 / P2

V2 = 3 × 101325 / 1333.22

V2 = 288 litres

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In Spanish

Dado que la temperatura es constante

Luego, usando la ley gay de Lussac

P1 • V1 / T1 = P2 • V2 / T2

Como la temperatura es constante

Entonces, T1 = T2 = T y se cancelan

Entonces, nos quedamos con

P1 • V1 = P2 • V2

Dado que, .

Volumen inicial

V1 = 3 litros.

Presión inicial

P1 = 1atm = 101325 Pa

Presión final

P2 = 10 mmHg = 1333.22 Pa

Entonces, queremos encontrar el volumen final V2

Hacer V2 sujeto de fórmula.

V2 = V1 • P1 / P2

V2 = 3 × 101325 / 1333.22

V2 = 288 litros

Entonces, el volumen final es de 288 litros

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