Rmm of N20 = (14X2) + 16 = 44
Percentage by mass of Nitrogen in N20 = 28/44x100 = 63.64
66x0.6634 = 43.7844g of Nitrogen in 66g of N20
Moles = Mass/Mr = 43.7844/14 = 3.13 moles
The amount of heat needed would be the specific heat multiplied by the mass of the substance and the temperature difference. In this case, the mass would be 75.0–g, the specific heat would be 0.449 j/g °c, and the temperature difference would be <span>1535 -25= 1510
Then the calculation would be: </span>0.449 j/g °c * 75g * 1510°c = 50,849.25J
In calorie it would be: 50849.25J / 4.184J/cal= 12,153.26 calorie
0.1m moles of solute particles are present in 1 L of each of the following aqueous solutions.
The number of moles of solute = mass of solute ÷ molar mass of solute, where mass is measured in grams and molar mass (defined as the mass of one mole of a substance in grams) is measured in g/mol
<h3>What is meant by moles of solute?</h3>
Molality is defined as moles of solute per kilogram of solvent. Molality = mass of solvent (in kg) moles of solute = molecular weight of solute × mass of solvent (in kg) mass of solute.
Learn more about moles of solute here:
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I believe that the chemical formula for an acid often begins with H, which means C is your answer.
In order to answer this question, we are going to look at the molar ratio between H2O and H2, we can see that by analyzing the numbers in front of the compounds, and we can see that the molar ratio is 2:2, this means that for every 2 moles of water decomposing, we will end up with 2 moles of H2 being produced, therefore the same amount of moles for H2O will be the same amount of moles of H2, which means that if we have 100 moles of H2O being decomposed, we will also have 100 moles of H2 being produced.