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2 years ago

6

-12=-8z+12 please need help

2 answers:

miss Akunina [59]2 years ago

8 0

Answer:

z=3

Step-by-step explanation:

-12=-8z+12

-12-12=-8z

-24=-8z

-24/-8=z

z=24/8

3=z

z=3

Alenkasestr [34]2 years ago

8 0

Answer and Step-by-step explanation:

To solve for z, we have to get everything away from z.

<u>First, subtract 12 from both sides of the equation.</u>

-24 = 8z

<u>Now, divide each side by 8.</u>

-3 = z

<u>z is equal to -3 (negative three).</u>

<u></u>

<u></u>

<em><u>#teamtrees #PAW (Plant And Water)</u></em>

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The roots of a quadratic equation depends on the discriminant $\Delta$ .

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A quadratic equation has the following format:

$y = ax^2 + bx + c$

It's roots are:

$y = 0$

Thus

$ax^2 + bx + c = 0$

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$\Delta = b^{2} - 4ac$

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A similar problem is given at brainly.com/question/19776811

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1 year ago

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Answer:

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2 years ago

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2 years ago

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Sveta_85 [38]

Answer:

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Step-by-step explanation:

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{4 x - 4 y = -48 | (equation 1)

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Swap equation 1 with equation 2:

{5 x - 6 y = -65 | (equation 1)

4 x - 4 y = -48 | (equation 2)

Subtract 4/5 × (equation 1) from equation 2:

{5 x - 6 y = -65 | (equation 1)

0 x+(4 y)/5 = 4 | (equation 2)

Multiply equation 2 by 5/4:

{5 x - 6 y = -65 | (equation 1)

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Add 6 × (equation 2) to equation 1:

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2 years ago

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zhenek [66]

Answer:

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Step-by-step explanation:

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