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andreev551 [17]
3 years ago
15

The half-life of tritium, or hydrogen-3, is 12.32 years. After about 24.6 years, how much of a sample of tritium will remain unc

hanged?
A. 1/8
B. 1/4
C. 1/3
D. 1/2
Chemistry
2 answers:
scoundrel [369]3 years ago
8 0

Answer: The correct option is B.

Explanation: This is an example of radioactive decay and all the radioactive decay processes follow First order of kinetics.

Expression for the half life of first order kinetics is:

t_{1/2}=\frac{0.693}{k}

We are given:

t_{1/2}=12.32years

Putting in above equation, we get:

12.32=\frac{0.693}{k}\\k=0.05625year^{-1}

Expression to calculate the amount of sample which is unchanged is:

N=N_oe^{-kt}

where,

N = Amount left after time t

N_o = Initial amount

k = Rate constant

t = time period

Putting value of k = 0.05625 and t = 24.6 in above equation, we get:

N=N_oe^{-0.05625\times 24.6}

\frac{N}{N_o}=0.25

The above fraction is the amount of sample unchanged and that is equal to \frac{1}{4}

Hence, the correct option is B.

Llana [10]3 years ago
6 0
The amount of the substance left after sometime, t, is given by the equation,
                                     At = (Ai) x e^-kt
where Ai is the initial amount and k is constant. From the given half-life,
                            At / Ai = 0.5 = e^-k(12.32)      ; k = 0.5626
Then, for the next set,
                             At/Ai = e^(-0.5626)x24.6 = 
Thus, the answer is letter B.
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The combination of a carbonyl group and a hydroxyl group on the same carbon atom is called a ________ group.
alukav5142 [94]

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d. carboxyl

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5 0
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The buffer is prepared by adding 250mL of 0.80M NH3 to 150mL of 0.50M NH4NO3. What is the pH of the final solution (Kb for NH3 =
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The pH of the solution is obtained to be 9.67.

<h3>What is a buffer?</h3>

A buffer is a solution that serves to militate against changes in acidity or alkalinity. The buffer is often made of a solution of a strong acid and its salt or a weak base and its salt.

Now we have the that;

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Number of moles of salt = 150/1000 *  0.50 = 0.075 moles

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pOH = pKb + log [salt/base]

pOH =  4.74 + log (0.1875/ 0.5)

pOH = 4.33

pH = 14 - 4.33

pH = 9.67

The pH of the solution is obtained to be 9.67.

Learn more about pH:brainly.com/question/15289741

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