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2 years ago

Demonstrate how you can prepare 250ml 0.25M hydrogen peroxide from a solution of 20g/100ml of hydrogen peroxide.

Chemistry

1 answer:

Nookie1986 [14]2 years ago

6 0

Answer:

Determine the volume of the initial solution,

, to produce the required solution. We do this by applying the dilution equation,

where M is the concentration and V is the volume, while the subscripts respectively depicts the initial and required solutions. Now, we must express the concentration of the initial solution in terms of moles per liter, wherein we use the conversion factors such as the molar mass, 34.015 g/mol, and 1000 mL/L. We proceed converting the concentration.

1000

34.015

1000

≈

5.88

Now, we are given the following values:

0.25

250

We proceed with the solution by applying the dilution equation and then plugging in the given values.

(

0.25

)

(

250

)

5.88

≈

Therefore, we need to take

of the initial solution and dilute it to the desired volume to produce the required solution.

that's the explanation but, this helps if ur in higher classes though :>

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The density of mercury is 5,427 kg/m3. If the density of water is 1.0 g/mL, will mercury float or sink in water?

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1 kg =1000 g = 10³ g,
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$\rm{\pink{\underline{\underline{\blue{REASON:-}}}}}$

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3 years ago

A gas at STP has a volume of 1.00 L. If the pressure is doubled and the temperature remains constant, what is the news of the ga

4vir4ik [10]

Answer: PV = nRT

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R is the gas constant which is 0.08206 L*atm/(K*mol)

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The temperature and number of moles are held constant. This means that this uses Boyle's Law. (The ideal gas law could be manipulated to give us this result when T and n are held constant.)

PV = k

where k is a constant.

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1 year ago

Using the average initial pH of your acetic acid solutions (2.96), and the average molarity of those solutions(.0602), calculate

Orlov [11]

Answer : The value of Ka for acetic acid is, $2.03\times 10^{-5}$

Explanation :

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Demonstrate how you can prepare 250ml 0.25M hydrogen peroxide from a solution of 20g/100ml of hydrogen peroxide.​

Demonstrate how you can prepare 250ml 0.25M hydrogen peroxide from a solution of 20g/100ml of hydrogen peroxide.