A balloon is inflated to a volume of 1.25L .If the temperature of the air inside is cooled from 35°C to 15°C , what will be the
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Answer:
The factor of increasing reaction rate is 1,85x10¹².
Explanation:
Using arrhenius formula:
Where k is rate constant; A is frecuency factor; Eₐ is activation energy; R is gas constant (0,008134 kJ/molK); T is temperature 25°C = 298,15K
Thus, replacing for an activation energy of 125 kJ/mol assuming A as 1:
k = 1,25x10⁻²²
When activation energy is 55kJ/mol:
k = 2,31x10⁻¹⁰
Thus, the factor of increasing reaction rate is:
2,31x10⁻¹⁰/1,25x10⁻²² =<em> 1,85x10¹²</em>
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I hope it helps!