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3 years ago

Somebody please help

Physics

1 answer:

suter [353]3 years ago

5 0

Answer:

a = 0.1067 [m/s²]

Explanation:

In order to solve this problem, we must first draw a free body diagram with the forces acting on it.

In the attached image we can find the free body diagram.

The net force can be found by performing a sum of forces on the X-axis, these forces are seen in the free body diagram.

∑Fx = Fr

where:

Fr = resultant force [N] (units of Newtons)

$F_{r}=275+275-310\\F_{r}=240[N]$

Acceleration can be found by means of Newton's second law, which tells us that the sum of the forces in a body or the resulting force is equal to the product of mass by acceleration.

∑F = m*a

where:

m = mass = 2250 [kg]

a = acceleration [m/s²]

$240=2250*a\\a=0.1067[m/s^{2} ]$

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Answer:

$\alpha = 6.431\,\frac{rad}{s^{2}}$

Explanation:

The pulley is modelled by the Newton's Laws, whose equation of equilibrium is:

$\Sigma M = T \cdot R = \frac{1}{2}\cdot M \cdot R^{2}\cdot \alpha$

Given that tension is equal to the weight of the bucket, the angular acceleration experimented by the pulley is:

$T = \frac{1}{2}\cdot M \cdot R \cdot \alpha$

$m_{b}\cdot g = \frac{1}{2}\cdot M \cdot R \cdot \alpha$

$\alpha = \frac{2\cdot m_{b}\cdot g}{M\cdot R}$

$\alpha = \frac{2\cdot (1.53\,kg)\cdot \left(9.807\,\frac{m}{s^{2}} \right)}{(7.07\,kg)\cdot (0.66\,m)}$

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2 years ago

A person fires a 38 gram bullet straight up into the air. It rises, then falls straight back down, striking the ground with a sp

Y_Kistochka [10]

Answer:

Force exerted = 25.41 kN

Explanation:

We have equation of motion

v² = u²+2as

u = 345 m/s, s = 8.9 cm = 0.089 m, v = 0 m/s

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Force exerted = 25409.83 N = 25.41 kN

4 0

3 years ago

A soccer player heads the ball and sends it flying vertically upwards at a speed of 18.0 m/s . How high above the players ' head

Irina-Kira [14]

Answer:

16.53 m

Explanation:

The following data were obtained from the question:

Initial velocity (u) = 18.0 m/s.

Final velocity (v) = 0 m/s

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Maximum height (h) =.?

The maximum height reached by the ball can be obtained as follow:

v² = u² – 2gh (since the ball is going against gravity)

0² = 18² – (2 × 9.8 × h)

0 = 324 – 19.6h

Rearrange

19.6h = 324

Divide both side by 19.6

h = 324 / 19.6

h = 16.53 m

Therefore, the maximum height reached by the ball is 16.53 m

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2 years ago

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Answer:

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Explanation:

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2 years ago

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dolphi86 [110]

Answer:

Explanation:

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p is the momentum

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We have the final answer as

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3 0

3 years ago

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