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Lina20 [59]
3 years ago
10

Somebody please help

Physics
1 answer:
suter [353]3 years ago
5 0

Answer:

a = 0.1067 [m/s²]

Explanation:

In order to solve this problem, we must first draw a free body diagram with the forces acting on it.

a)

In the attached image we can find the free body diagram.

b)

The net force can be found by performing a sum of forces on the X-axis, these forces are seen in the free body diagram.

∑Fx = Fr

where:

Fr = resultant force [N] (units of Newtons)

F_{r}=275+275-310\\F_{r}=240[N]

c)

Acceleration can be found by means of Newton's second law, which tells us that the sum of the forces in a body or the resulting force is equal to the product of mass by acceleration.

∑F = m*a

where:

m = mass = 2250 [kg]

a = acceleration [m/s²]

240=2250*a\\a=0.1067[m/s^{2} ]

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A 4g bullet, travelling at 589m/s embeds itself in a 2.3kg block of wood that is initially at rest, and together they travel at
VARVARA [1.3K]

Answer:

The  percentage of the kinetic energy that is left in the system after collision to that before is 0.174 %

Explanation:

Given;

mass of bullet, m₁ = 4g = 0.004kg

initial velocity of bullet, u₁ = 589 m/s

mass of block of wood, m₂ = 2.3 kg

initial velocity of the block of wood, u₂ = 0

let the final velocity of the system after collision = v

Apply the principle of conservation of linear momentum

m₁u₁ + m₂u₂ = v(m₁+m₂)

0.004(589) + 2.3(0) = v(0.004 + 2.3)

2.356 = 2.304v

v = 2.356 / 2.304

v = 1.0226 m/s

Initial kinetic energy of the system

K.E₁ = ¹/₂m₁u₁² + ¹/₂m₂u₂²

K.E₁ = ¹/₂(0.004)(589)² = 693.842 J

Final kinetic energy of the system

K.E₂ = ¹/₂v²(m₁ + m₂)

K.E₂ = ¹/₂ x 1.0226² x (0.004 + 2.3)

K.E₂ = 1.209 J

The kinetic energy left in the system = final kinetic energy of the system

The percentage of the kinetic energy that is left in the system after collision to that before = (K.E₂ / K.E₁) x 100%

                       = (1.209 / 693.842) x 100%

                        = 0.174 %

Therefore, the  percentage of the kinetic energy that is left in the system after collision to that before is 0.174 %

6 0
4 years ago
We know that charged objects with the same sign repel each other and objects charged with opposite signs attract. What happens w
choli [55]

solution:

When an uncharged conducting object brought near to a charged insulating object there is a force on the conducting object to move the electrons within it to opposite sides of the conductor. That means there is a separation of charges in the conducting object in the presence of the charged insulating object near to it but the charge on the conducting object is neutral.

Thus, the conducting object is uncharged.

There is a force of attraction between the uncharged conducting object and the insulating object when it brought near to the insulating object.

Thus, there is a force on the conducting object.

The conductor remains uncharged and a force is exerted on it.


3 0
3 years ago
Three batteries are connected in series so that the total voltage is 54 volts. The voltage of the first battery is twice the vol
Alex_Xolod [135]

Answer:

v_1 = 12 volts

v_2 = 6 volts

v_3 = 36 volts

Explanation:

As we know that all the batteries are in series

so the net voltage of all three batteries is given as

V = v_1 + v_2 + v_3

now we know that

v_1 = 2v_2

v_1 = \frac{1}{3}v_3

now plug in all the values in it

54 = v_1 + \frac{v_1}{2} + 3v_1

54 = 4.5 v_1

v_1 = 12 volts

now we have

v_2 = 6 volts

v_3 = 36 volts

3 0
3 years ago
A train traveled 85 mph for 7 hours how far did it travel?
Sergio [31]

Answer:

12.1429 miles per hour

Explanation:

4 0
3 years ago
Read 2 more answers
Once​ Kate's kite reaches a height of 52 ft ​(above her​ hands), it rises no higher but drifts due east in a wind blowing 6 ft d
Andru [333]

Answer:

5.213ft

Explanation:

Z² = x² + y²

x = √(z² - y²)

y = 52ft, dx = 6ft, z = 105ft, dz = ?

d(z² = x² + y²)

2zdz = 2xdx

dz = xdx/z

But x = √(z² - y²)

dz = √(z² - y²)/z * dx

dz = [√(105² - 52²)/105] * 6

dz = √(8521)/ 17.5

dz = 5.213ft

7 0
3 years ago
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