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Lina20 [59]
3 years ago
10

Somebody please help

Physics
1 answer:
suter [353]3 years ago
5 0

Answer:

a = 0.1067 [m/s²]

Explanation:

In order to solve this problem, we must first draw a free body diagram with the forces acting on it.

a)

In the attached image we can find the free body diagram.

b)

The net force can be found by performing a sum of forces on the X-axis, these forces are seen in the free body diagram.

∑Fx = Fr

where:

Fr = resultant force [N] (units of Newtons)

F_{r}=275+275-310\\F_{r}=240[N]

c)

Acceleration can be found by means of Newton's second law, which tells us that the sum of the forces in a body or the resulting force is equal to the product of mass by acceleration.

∑F = m*a

where:

m = mass = 2250 [kg]

a = acceleration [m/s²]

240=2250*a\\a=0.1067[m/s^{2} ]

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A 1.53-kg bucket hangs on a rope wrapped around a pulley of mass 7.07 kg and radius 66 cm. This pulley is frictionless in its ax
levacccp [35]

Answer:

\alpha = 6.431\,\frac{rad}{s^{2}}

Explanation:

The pulley is modelled by the Newton's Laws, whose equation of equilibrium is:

\Sigma M = T \cdot R = \frac{1}{2}\cdot M \cdot R^{2}\cdot \alpha

Given that tension is equal to the weight of the bucket, the angular acceleration experimented by the pulley is:

T = \frac{1}{2}\cdot M \cdot R \cdot \alpha

m_{b}\cdot g = \frac{1}{2}\cdot M \cdot R \cdot \alpha

\alpha = \frac{2\cdot m_{b}\cdot g}{M\cdot R}

\alpha = \frac{2\cdot (1.53\,kg)\cdot \left(9.807\,\frac{m}{s^{2}} \right)}{(7.07\,kg)\cdot (0.66\,m)}

\alpha = 6.431\,\frac{rad}{s^{2}}

7 0
2 years ago
A person fires a 38 gram bullet straight up into the air. It rises, then falls straight back down, striking the ground with a sp
Y_Kistochka [10]

Answer:

Force exerted = 25.41 kN

Explanation:

We have equation of motion

      v² = u²+2as

u = 345 m/s, s = 8.9 cm = 0.089 m, v = 0 m/s

     0² = 345²+2 x a x 0.089

       a = -668679.78 m/s²

Force exerted = Mass x Acceleration

Mass of bullet = 38 g = 0.038 kg

Acceleration = 668679.78 m/s²

Force exerted = 25409.83 N = 25.41 kN

4 0
3 years ago
A soccer player heads the ball and sends it flying vertically upwards at a speed of 18.0 m/s . How high above the players ' head
Irina-Kira [14]

Answer:

16.53 m

Explanation:

The following data were obtained from the question:

Initial velocity (u) = 18.0 m/s.

Final velocity (v) = 0 m/s

Acceleration due to gravity (g) = 9.8 m/s²

Maximum height (h) =.?

The maximum height reached by the ball can be obtained as follow:

v² = u² – 2gh (since the ball is going against gravity)

0² = 18² – (2 × 9.8 × h)

0 = 324 – 19.6h

Rearrange

19.6h = 324

Divide both side by 19.6

h = 324 / 19.6

h = 16.53 m

Therefore, the maximum height reached by the ball is 16.53 m

6 0
2 years ago
What is the longitud of the middle of Romano swamp
OverLord2011 [107]

Answer:

37 W 47 N

Explanation:

5 0
2 years ago
A 7.50 kg bowling ball has 70.4<br> kg•m/s of momentum. What is its<br> velocity?
dolphi86 [110]

Answer:

<h2>9.39 m/s</h2>

Explanation:

The velocity of the bowling ball can be found by using the formula

v =  \frac{p}{m}  \\

p is the momentum

m is the mass

From the question we have

v =  \frac{70.4}{7.5}  \\  = 9.38666666..

We have the final answer as

<h3>9.39 m/s</h3>

Hope this helps you

3 0
3 years ago
Read 2 more answers
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