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1 answer:
Answer:
a = 0.1067 [m/s²]
Explanation:
In order to solve this problem, we must first draw a free body diagram with the forces acting on it.
a)
In the attached image we can find the free body diagram.
b)
The net force can be found by performing a sum of forces on the X-axis, these forces are seen in the free body diagram.
∑Fx = Fr
where:
Fr = resultant force [N] (units of Newtons)
c)
Acceleration can be found by means of Newton's second law, which tells us that the sum of the forces in a body or the resulting force is equal to the product of mass by acceleration.
∑F = m*a
where:
m = mass = 2250 [kg]
a = acceleration [m/s²]
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Answer:
Electric field at a point ( x , y , z) is .
Explanation:
Given :
Electric potential in the region is ,
We need to find the electric field .
We know , electric field , { Here r is distance }
In coordinate system ,
{
is partial derivative }
Putting all values we get ,
Hence , this is the required solution.
Answer:s=0.68 m
Explanation:
Given
Inclination
Speed of block(u)=1.6 m/s
Coefficient of kinetic Friction
deceleration provided by friction=g\sin \theta -\mu _kg\cos \theta [/tex]
Using
Final velocity v=0
s=0.68 m
Answer:
d = 68.5 x 10⁻⁶ m = 68.5 μm
Explanation:
The complete question is as follows:
An optical engineer needs to ensure that the bright fringes from a double-slit are 15.7 mm apart on a detector that is 1.70m from the slits. If the slits are illuminated with coherent light of wavelength 633 nm, how far apart should the slits be?
The answer can be given by using the formula derived from Young's Double Slit Experiment:
where,
d = slit separation = ?
λ = wavelength = 633 nm = 6.33 x 10⁻⁷ m
L = distance from screen (detector) = 1.7 m
y = distance between bright fringes = 15.7 mm = 0.0157 m
Therefore,
<u>d = 68.5 x 10⁻⁶ m = 68.5 μm</u>
Answer:
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Explanation:
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